If SU bisects TSV, then TSU = USV
4y + 11 = 6y + 5
6y - 4y = 11 - 5 = 6
y = 6/2 = 3
Therefore, m<TSU = 4(3) + 11 = 12 + 11 = 23
Step-by-step explanation:
x⁴ − 5x³ + 11x² − 25x + 30
x⁴ − 5x³ + 6x² + 5x² − 25x + 30
x² (x² − 5x + 6) + 5 (x² − 5x + 6)
(x² + 5) (x² − 5x + 6)
(x² + 5) (x − 2) (x −3)
The zeros are 2, 3, and ±√5i.
Answer:
Step-by-step explanation:
Did you find the answer
Answer:
0.281 = 28.1% probability a given player averaged less than 190.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
A bowling leagues mean score is 197 with a standard deviation of 12.
This means that 
What is the probability a given player averaged less than 190?
This is the p-value of Z when X = 190.



has a p-value of 0.281.
0.281 = 28.1% probability a given player averaged less than 190.