Answer:
Increased by, added, brought up (All I know of haha)
Step-by-step explanation:
Theres really no explanation to this other than learning your mathematical terms.
A. Alright, we want to multiply one equation by a constant to make it cancel out with the second. Since the first equation has a "blank" y, let's multiply the first equation by <em>2</em>.
3x-y=0 → 2(3x-y=0) = 6x - 2y = 0
5x+2y=22
The answer for this part would be: 6x - 2y = 0 and 5x + 2y = 22
B. So now we combine them:
6x - 2y = 0
+ + +
5x + 2y = 22
= = =
11x + 0 = 22 ← The answer
C. Now that we have the equation 11x = 22, we solve for x
11x = 22 ← Divide both sides by 11
x = 2 ← The answer
D. Now that we have x=2, we plug that back in to 5x+2y=22 and solve for y:
5(2)+2y = 22
10 + 2y = 22
2y = 12
y = 6
<u>Therefore, the solution to this problem is x = 2 and y = 6</u>
6p+p+2-3=8p-8
7p-1=8p-8
1=1p-8
7=1p
p=7
Answer:
QR = 5.
Step-by-step explanation:
Because the parallelograms are similar then the corresponding sides are in the same ratio.
So AB / PQ = BC / QR
9/3 = 15 / QR
15 / QR = 3
QR = 15/3
= 5. (answer)
by
![t\in[0,1]](https://tex.z-dn.net/?f=t%5Cin%5B0%2C1%5D)
. Then 
