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3 years ago

If F(x)=3x-2/6 which of the following is the inverse of F(x)?

Mathematics

1 answer:

lana66690 [7]3 years ago

6 0

Answer:

Step-by-step explanation:

I'm seeing that f(x) is

$\frac{3x-2}{6}$

What you do to find an inverse is switch the x and y coordinates and then solve for the new y. Switching the x and y gives us:

$x=\frac{3y-2}{6}$

Now we have to solve for the new y. Begin by muliplying both sides by 6 to get:

6x = 3y - 2 and

6x + 2 = 3y so

2x + 2/3 = y

To put it back into function notation:

$f^{-1}(x)=2x+\frac{2}{3}$

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What is the simplified value of the exponential expression 16^1\4

Natalka [10]

If you observe that $16 = 2^4$ , you can rewrite the expression as

$16^{\frac{1}{4}} = (2^4)^{\frac{1}{4}}$

Now, if you use the exponent rule $(a^b)^c = a^{bc}$ , you may rewrite the expression again:

$(2^4)^{\frac{1}{4}} = 2^{4\cdot\frac{1}{4}} = 2^1 = 2$

6 0

3 years ago

Graph the function f(x) = x3 – 5x2 + 6x using the graphing calculator. What are the solutions to the related equation? Check all

Juli2301 [7.4K]

the solutions to the related equation are 0,2,3 .

<u>Step-by-step explanation:</u>

Here we have , function f(x) = x3 – 5x2 + 6x . Graph of this function is given below . We need to find What are the solutions to the related equation . Let's find out:

Solution of graph means the value of x at which the value of f(x) or function is zero . We can determine this by seeing the graph as at what value of x does the graph intersect or cut x-axis !

At x = 0 .

From the graph , at x=0 we have f(x) = 0 i.e.

⇒ $f(x) = x^3- 5x^2 + 6x$

⇒ $f(0) = 0^3- 5(0)^2 + 6(0)$

⇒ $f(0) =0$

At x = 2 .

From the graph , at x=2 we have f(x) = 0 i.e.

⇒ $f(x) = x^3- 5x^2 + 6x$

⇒ $f(0) = 2^3- 5(2)^2 + 6(2)$

⇒ $f(0) =0$

At x=3 .

From the graph , at x=3 we have f(x) = 0 i.e.

⇒ $f(x) = x^3- 5x^2 + 6x$

⇒ $f(0) = 3^3- 5(3)^2 + 6(3)$

⇒ $f(0) =0$

Therefore , the solutions to the related equation are 0,2,3 .

3 0

3 years ago

Please help, the question says what statement best describes the placement of the lines Carson Drew

blagie [28]

Answer:

Only line A is a well-placed line of best fit.

Step-by-step explanation:

I did this on Plato and got it correct.

7 0

2 years ago

I think it the third one but need a double check

makkiz [27]

Answer:

The first answer is correct.

Step-by-step explanation:

Line 5 says that the reason is due to substitution

Line 3 says m∠ SQT equals 180°

If we substitute 180° into the spot for m∠ SQT in line 4, we get solution option 1

8 0

2 years ago

PLEASEEE I DONT KNOW HOW TO DO ITTTT. THE 35.8 IS RIGHT BUT I CANT GET MEASURE OF ANGLE C AND A I GOT 46.2 for A AND 70.8 for C

Rashid [163]

Answer:

Hope it helps....!!!!!

Step-by-step explanation:

AB = c = 38

BC = a = 29

AC = b

Angle ABC = 63 degrees

Solving for AC "b":

Cosine rule: c^2 = a^2 * b^2 -2ab * cos C

38^2 = 29^2 * b^2 - (2* 29) * b * (cos 38)

1444 = 841 * b^2 - 58 * b * 0.955

(1444 + 58)/0.955 = b^2 * b

1572.77486911 = b^3

11.62935 = b

11.63 = b (rounded to two decimal places)

Now solving for angle A:

Sine rule: a/sinA = b/sinB

29/sinA = 11.63/sin(63)

sinA/29 = sin(63)/11.63

sin A = (sin(63)/11.63) * 29

sin A = 0.41731

A = sin^-1 (0.41731)

A = 24 degrees 39 minutes 53 seconds

Now solving for angle C:

Sine rule: c/sinC = b/sinB

38/sinC = 11.63/sin(63)

sinC/38 = sin(63)/11.63

sin C = (sin(63)/11.63) * 38

sin C = 0.54682

C = sin^-1 (0.54682)

C = 33 degrees 8 minutes 56 seconds

3 0

2 years ago