Answer:
Step-by-step explanation:
Restaurant A data in ascending order : 67 68 72 89 96 97 120 124
Restaurant B data in ascending order : 49 56 76 78 95 98 115 126
<em>Restaurant A</em>
- Mean =
= 91.625 - Median = Since there are even number of observations so,
=
=
= 92.5
- Mid range =
=
= 28.5 - Range = Highest value - Lowest value = 124 - 67 = 57
- Variance =
,where Xi are sample values and
is mean
Solving above equation we get, variance = 493.982
- Standard Deviation =
= 22.226
<em>Restaurant B</em>
- Mean =
= 74.375
- Median = Since there are even number of observations so,
=
=
= 86.5
- Mid Range =
=
= 38.5
- Range = Highest value - Lowest value = 126 - 49 = 77
- Variance =
,where Xi are sample values and
is mean
= 727.982
- Standard Deviation =
= 26.981
Now comparing the results of two restaurants we conclude that:
- Restaurant A on an average takes more time for drive-through service than Restaurant B.
- Median time for Restaurant A is also more than Restaurant B.
- Restaurant B has more variation in time taken for drive through service as the variance & standard deviation of Restaurant B is more than A.
- There is more spread in the time data for Restaurant B as it has more range than A.
Two solutions were found :<span><span> n = -5/2 = -2.500
</span><span> n = 13/2 = 6.500</span></span>
The right answer is Option D: 43 items
Step-by-step explanation:
Time taken to scan each item = 2 seconds
Time taken to process the payment = 40 seconds
Let,
x be the number of items bought
y be the total time
y = 2x+40 Eqn 1
Now
Total time = 2 minutes and 6 seconds
1 minute = 60 seconds
2 minutes = 2*60 = 120 seconds
Total time = 120+6 = 126 seconds
Putting y=126 in Eqn 1

Dividing both sides by 2

43 items are being purchased.
The right answer is Option D: 43 items
Keywords: addition, division
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