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3 years ago

Which set of data is displayed in the box plot below?

Mathematics

1 answer:

Karolina [17]3 years ago

6 0

Answer:

It would tske to long for me to break it down but my best bet is B

Step-by-step explanation:

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On a piece of paper, use a protractor to construct a triangle with angle measures of 40 degrees and 60 degrees.

Andru [333]

Answer:

Step-by-step explanation

Well every triangle has to equal 180 degrees.

So you would add the two degrees you already have, which on this one you would get 100.

Then, you would subtract that number from 180 to get 80.

Hope this helps you!!

8 0

3 years ago

Read 2 more answers

Wht is 39% of 1,200? I can't understand it

Gennadij [26K]

Something percent of a number must be smaller than the number.
And also, 39% of a number is equal to 39/100 multiplied by the number.

Thus:
39/100 * 1200
39/1 * 12
468

8 0

3 years ago

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Which expression is equivalent to (4^5/4 4^1/4/4^12)^1/2

vitfil [10]

Answer:

43 2/3

Step-by-step explanation:

8 0

3 years ago

1.Ordenar de menor a mayor los siguientes números

Nataliya [291]

1. -16, -9, -3, 0, 5, 8, 25

2. 26, 13, 7, 6, 2, -1, -3, -50

Espero que esto ayude!

8 0

3 years ago

Read 2 more answers

You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o

Aleksandr [31]

Answer:

Therefore the circumference of the circle is $=\frac{20\pi}{4+\pi}$

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

$\Rightarrow s=\frac{10-\pi r}{2}$

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

$A=\pi r^2+ (\frac{10-\pi r}{2})^2$

$\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2$

$\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}$

$\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25$

For maximum or minimum $\frac{dA}{dr}=0$

Differentiating with respect to r

$\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi$

Again differentiating with respect to r

$\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}$ > 0

For maximum or minimum

$\frac{dA}{dr}=0$

$\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0$

$\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}$

$\Rightarrow r=\frac{10}{4+\pi}$

$\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0$

Therefore at $r=\frac{10}{4+\pi}$ , A is minimum.

Therefore the circumference of the circle is

$=2 \pi \frac{10}{4+\pi}$

$=\frac{20\pi}{4+\pi}$

4 0

2 years ago