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Neko [114]
4 years ago
9

The fifth -grade students participating in the math competition will be evenly divided into teams of 3 students each. How many s

tudents could be participating?
Mathematics
1 answer:
Basile [38]4 years ago
5 0

Answer:

There could be an infinite amount of teams but to make it easy you could just say 5 teams which would be 15 students.

Step-by-step explanation:

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valina [46]
This is a simple "solve for x" equation.
5k-2k=12
3k=12
k=4
You should try doing some more on your own, as this will be coming up a lot in the future.
5 0
3 years ago
Which relation is not a function?
Margaret [11]

Answer:

Step-by-step explanation:

okay

6 0
3 years ago
Scientists have found a relationship between the temperature and the height above a distant planet's surface. , given below, is
ikadub [295]

The question is incomplete, the complete question is below:

Scientists have found a relationship between the temperature and the height above a distant planet's surface. , given below, is the temperature in Celsius at a height of kilometers above the planet's surface. The relationship is as follows: T(h) = 30.5 -2.5h.

a) Calculate T^-1(x)

b) T^-1(15)

Answer:

a) T^{-1} (x)= \frac{30.5-x}{2.5}

b) 6.2 °C

Step-by-step explanation:

a) T(h) = 30.5 - 2.5h\\2.5h = 30.5-T(h)\\h = \frac{30.5-T(h)}{2.5}\\ T^{-1} (x)= \frac{30.5-x}{2.5}

b) T^{-1} (x)= \frac{30.5-x}{2.5}\\\\T^{-1} (15)= \frac{30.5-15}{2.5}=6.2

3 0
3 years ago
What is the quotient of 23 and 56?
dedylja [7]

Answer:

0.410714

Step-by-step explanation:

Dividend ÷ Divisor = Quotient

6 0
3 years ago
The human eye can sharply see objects within a 15 Dagrees horizontal angle either side of the direction of focus. Arlo is design
faltersainse [42]

Answer:

Maximum width of image that can be viewed clearly on the cylindrical screen is 10 ft

Step-by-step explanation:

Here we have

Circumference of screen = 2πr = 120 ft

Angle that can be viewed horizontally either side of focus = 15°

Total angle view = 30°

Size of image that can be viewed = Object within 30° of focus

Maximum width of image that can be viewed clearly = Perimeter of 30° arc section of cylinder

Maximum width of image that can be viewed clearly = 30/360×120 ft = 10 ft.

Maximum width of image that can be viewed clearly on the cylindrical screen = 10 ft.

6 0
3 years ago
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