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2 years ago

the length of a rectangle is 4 times its width. The rectangles perimeter is 68 feet what is the rectangles length and width ??

Mathematics

1 answer:

kodGreya [7K]2 years ago

7 0

Answer:

Length = 27.2

Width = 6.8

Step-by-step explanation:

P = L+L+W+W

68 = 4(L+L)+W+W

68 = 4(x+x)+x+x

68 = 4x+4x+x+x

68 = 10x

x = 6.8

L = 4x

L = 27.2

W = x

W = 6.8

68 = 27.2+27.2+6.8+6.8

68 = 68

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alisha [4.7K]

$(a + b)^2 = a^2 + 2ab + b^2$

$(\dfrac{1}{4}A + \dfrac{1}{4}B)^2 =$

$= \dfrac{1}{16}A^2 + \dfrac{1}{8}AB + \dfrac{1}{16}B^2$

Answer: A.

Another way to solve by factoring 1/4.

$(\dfrac{1}{4}A + \dfrac{1}{4}B)^2 =$

$= [\dfrac{1}{4}(A + B)]^2$

$= (\dfrac{1}{4})^2(A + B)^2$

$= \dfrac{1}{16}(A^2 + 2AB + B^2)$

$= \dfrac{1}{16}A^2 + \dfrac{1}{16}2AB + \dfrac{1}{16}B)^2$

$= \dfrac{1}{16}A^2 + \dfrac{1}{8}AB + \dfrac{1}{16}B)^2$

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3 years ago

Read 2 more answers

How do I find this help please

KIM [24]

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3 years ago

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Answer:

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