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3 years ago

How to do the problem

Mathematics

1 answer:

trapecia [35]3 years ago

4 0

Step-by-step explanation:

$g(0.5) = 2 \\ \\ h(x) = g(x).f(x) \\ \therefore \: h(2) = g(2).f(2) \\ \therefore \: h(2) = 5 \times 2\\ \therefore \: h(2) = 10\\ \\ \\ j(x) = g(x) - f(x) \\ \therefore \: j(4) = g(4) - f(4) \\ \therefore \: j(4) = 9 - 8\\ \therefore \: j(4) = 1\\ \\ \\$

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dezoksy [38]

The answer will be 0.4 .

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If alpha and bita are the zeroes of the polynomial f(x)=x^-5x+k such that alpha - bita =1, then find the value of k

vovangra [49]

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2 years ago

Reduce the fraction -20t5u2v3 / 48t7u4v .

kondor19780726 [428]

Deal with the numbers and variables step by step

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3 years ago

Please help! x^3 +y^3=9

Crank

Step-by-step explanation:

Taking the derivative of both sides with respect to x, we get

$\dfrac{d}{dx}(x^3 + y^3) = \dfrac{d}{dx}(3)$

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2 years ago

A music teacher asked 23 students in the band how many hours they practiced playing their instrument each week. The results are

valkas [14]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

A music teacher asked 23 students in the band how many hours they practiced playing their instrument each week. The results are shown in the dot plot. Which statement best describes the data?

a. The data are skewed left, so most student's practice times are more than the mean practice time.

b. The data are skewed left, so most student's practice times are less than the mean practice time.

c. The data are skewed right, so most student's practice times are less than the mean practice time.

d. The data are skewed right, so most student's practice times are more than the mean practice time.

Answer:

The correct option is a.

The data are skewed left, so most student's practice times are more than the mean practice time.

Step-by-step explanation:

Refer to the attached box plot which shows number of hours the students spent on practice for playing their instrument each week.

When the data distribution is not symmetric around the mean then it is either skewed to right or skewed to left.

The given box plot is skewed to the left since the tail of the distribution on the left side is longer than the right side or in other words, most of the data is leaning to the right side of the curve.

Due to this, most student's practice times are more than the mean practice time.

A left skewed distribution is also known as negatively skewed distribution.

Therefore, we can conclude that the correct option is a.

a. The data are skewed left, so most student's practice times are more than the mean practice time.

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3 years ago