What is the measure of the vertex angle of an isosceles triangle if one of its base angles measures 65° and its congruent sides
1 answer:
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the correct question in the attached figure
(2^5)/8=2^2
we have
8----------- >2^3
(2^5)/8----------- > (2^5)/(2^3)=2^(5-3)=2^2
therefore
2^2=2^2-- ------> is ok
the answer is by simplifying 8 to 2^3 to make both powers base two and subtracting the exponents
