Answer:
91
Step-by-step explanation:
Let
x = first number
x+1 = second number
x+2 = third number
x+3 = fourth number
Total = 182
x + x + 1 + x + 2 + x + 3 = 182
4x + 6 = 182
Subtract 6 from both sides
4x + 6 - 6 = 182 - 6
4x = 176
Divide both sides by 4
x = 176 / 4
= 44
x = 44
x = 44
x+1 = 44 + 1 = 45
x+2 = 44 + 2 = 46
x+3 = 44 + 3 = 47
Sum of the two middle numbers = 45 + 46
= 91
Answer:
Step-by-step explanation:
From the total pool of colored balls, one can choose 2 reds, 2 blacks, 3 whites, and 2 blues in

ways.
I'm assuming no ball of the same color is distinguishable from any other ball of the same color. So when I'm considering the possible arrangements, if I had lined up the ball as
red1 - black - red2 - ...
then this would be no different that
red2 - black - red1 - ...
So I now have 9 balls to arrange, which means there are

total possible permutations of them. But order among distinct colors is assumed to not matter. This means I have to divide the total number of permutations by the number of ways I could permute balls of the same color. Then there would be a total of

ways of arranging the balls I had selected.