Question

Which angle forms a y-coordinate on a unit circle of /~3/2 (square root of 3 over 2)

Answer 1

Answer:

$\theta=60\degree$

Or

$\theta=\frac{\pi}{3}$

Step-by-step explanation:

We want to find the angle which forms a y-coordinate of $\frac{\sqrt{3} }{2}$

on the unit circle.

The y-coordinate on the unit circle is given by $\sin(\theta)$.

This implies that  $\sin(\theta)=\frac{\sqrt{3} }{2}$

$\Rightarrow \theta=\sin^{-1}(\frac{\sqrt{3} }{2})$

$\Rightarrow \theta=\sin^{-1}(\frac{\sqrt{3} }{2})$

$\Rightarrow \theta=60\degree$

Or

$\theta=\frac{\pi}{3}$