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Leto [7]
3 years ago
13

When 43,55 and 67 are divided by a certain number, the remainder is 7 in each case. Find the number? ​

Mathematics
1 answer:
siniylev [52]3 years ago
5 0

Answer:

12

Step-by-step explanation:

First subtract 7 from 43, 55 and 67

43 - 7 = 36 ;  55 - 7 = 48  ;  67 - 7 = 60

Now find the GCF of 36 , 48 , 60

36 = 2 * 2 * 3 * 3

48 = 2 * 2 * *2*2 * 3

60 = 2 * 2 * 3 * 5

GCF = 2 * 2 * 3 = 12

The required number is 12

When you divide 43 by 12, the remainder is 7.

When you divide 55 by 12, the remainder is 7

When you divide 67 by 12, the remainder is 7

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A company advertises that its cans of caviar each contain 100 g of their product. A consumer advocacy group doubts this claim, a
Blizzard [7]

Answer:

The value of the test statistic is -3.14.

Step-by-step explanation:

Test statistic:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the expected value, \sigma is the standard deviation and n is the size of the sample.

A company advertises that its cans of caviar each contain 100 g of their product.

This means that \mu = 100

They calculate a sample mean weight of 99 g and a sample standard deviation of 0.9 g. Sample of 8 cans.

This means that X = 99, \sigma = 0.9, n = 8

So the test statistic will be given by:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

t = \frac{99 - 100}{\frac{0.9}{\sqrt{8}}}

t = -3.14

The value of the test statistic is -3.14.

8 0
3 years ago
Find the constant of variation (k) where y varies directly with x. y = 2, when<br> X = 6.
ExtremeBDS [4]

Answer:

The graph below models the value of a $20,000 car t years after it was purchased.

                    Value of Car

A graph titled Value of Car has years on the x-axis and Dollars on the y-axis. A line curves down and goes through points (0, 20,000), (4, 10,000), and (14, 2,000).

Which statement best describes why the value of the car is a function of the number of years since it was purchased?

Each car value, y, is associated with exactly one time, t.

Each time, t, is associated with exactly one car value, y.

The rate at which the car decreases in value is not constant.

There is no time, t, at which the value of the car is 0.

Step-by-step explanation:

7 0
3 years ago
How do I solve this?
iris [78.8K]

Answer:

Step-by-step explanation:

From the picture attached,

Addition of the blocks in first row is 60

a + a + a + 12 = 60

3a + 12 = 60

3a = 60 - 12

3a = 48

a = 16

For second row,

(b + 5) + (b + 5) + (b + 5) + (b + 5) = 60

4(b + 5) = 60

b + 5 = 15

b = 10

For third row,

(a + b) + c = (b + 5) + (b + 5) + (b + 5)

a + b + c = 3(b + 5)

16 + 10 + c = 3(10 + 5) [Since, a = 16 and b = 10}

26 + c = 45

c = 45 - 26

c = 19

For fourth row,

3c + d = 60

3(19) + d = 60

57 + d = 60

d = 60 - 57

d = 3

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3 years ago
2 &gt; s-2<br> line under &gt;
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Express 0.32 as a fraction
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