9m+2=3m-10
subtract 3m from both sides to get:
6m+2=-10
subtract 2 from both sides to get:
6m=-12
finally, divide by 6 on both sides to get what m equals:
m=-2
Answer:
Step-by-step explanation:
new length=15+x
width=19+x
then area=(15+x)×(19+x)=285+15x+19x+x²=x²+34x+285 ft²
original area=15×19=285 ft²
then 285+98=x²+34x+285
or
x²+34x-98=0
x²+34x+17²=98+17²
(x+17)²=98+289=387
x+17=√387=3√43
x=3√43-17 ft
1st quartile: 11
median: 38.50000
3rd quartile: 45
<h3>According to the given information:</h3>
- Order these numbers in increasing order: 6, 7, 15, 36, 41, 43, 47, 49
- There is a 38.5 median (it is the mean of 36 and 41 - the pair of middle entries).
- 6,7,15,36, or the left-most half of the data, make up the sample.
- The median of the lower half is 11, which is the first quartile (it is the mean of 7 and 15 - the pair of middle entries).
- 41, 43, 47, and 49, which are the data points in the upper half, are to the right of the median.
- The median of the upper half is 45 in the third quartile (it is the mean of 43 and 47 - the pair of middle entries).
- The biggest value deviates 10.5 from the median (49-38.5)
Measure descriptive statistics
1st quartile: 11
median: 38.50000
3rd quartile: 45
To know more about quartile visit:
brainly.com/question/8737601
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I understand that the question you are looking for is :
2 Drag the tiles to the boxes to form correct pairs. Match the values associated with this data set to their correct descriptions. {6, 47, 49, 15, 43, 41, 7, 36} first quartile 38.5 median 11 third quartile 10.5 the difference of the largest value and the median 45
Answer:
2n-4
Step-by-step explanation:
-n-2+3n-2 (here I distributed the negative to both parts)
2n-4 (gather the like terms)
<h3>
Answer: Choice B</h3>
=========================================================
Explanation:
The rule we use is
![\Large a^{m/n} = \sqrt[n]{a^m} = \left(\sqrt[n]{a}\right)^m](https://tex.z-dn.net/?f=%5CLarge%20a%5E%7Bm%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Ba%5Em%7D%20%3D%20%5Cleft%28%5Csqrt%5Bn%5D%7Ba%7D%5Cright%29%5Em)
where 'a' is the base, m stays in the role of the exponent, and n plays the role of the root index (eg: n = 3 is a cube root, n = 4 is a fourth root, and so on).
So for instance,
![\Large 2^{3/4} = \sqrt[4]{2^3} = \left(\sqrt[4]{2}\right)^3](https://tex.z-dn.net/?f=%5CLarge%202%5E%7B3%2F4%7D%20%3D%20%5Csqrt%5B4%5D%7B2%5E3%7D%20%3D%20%5Cleft%28%5Csqrt%5B4%5D%7B2%7D%5Cright%29%5E3)
or in this case,
![\Large t^{5/8} = \sqrt[8]{t^5} = \left(\sqrt[8]{t}\right)^5](https://tex.z-dn.net/?f=%5CLarge%20t%5E%7B5%2F8%7D%20%3D%20%5Csqrt%5B8%5D%7Bt%5E5%7D%20%3D%20%5Cleft%28%5Csqrt%5B8%5D%7Bt%7D%5Cright%29%5E5)
