First, we need to see how to get from one even integer to another. Well, what do you do to get from 2 to 4? 4 to 6? You add 2. If x is even, then the next even number must be x+2, and then the next x+4, and x+6, and so on. Since we're only going 3, we have:
x + (x+2) + (x+4) = 126. Now we can just solve the equation!
x + x + 2 + x + 4 = 126
3x + 6 = 126.
3x = 120.
x=40. But is that your answer? Nope! Don't forget, the problem says that <em>x is the smallest number out of the 3</em>. Which means 40 + 2 is the middle number, and 40 + 4 = 44 is the greatest.
Your answer is 44.
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</em><em><u /><u>Don't forget to rate this answer the </u><u>Brainliest</u><u>!</u></em>
Are there choices to the answer or must you draw the graph?
If you can please attach images so I can help :)
Use a graphing tool and you'll see a circle form. This circle has a center of (0,0) and radius of 4. Side note: this equation is equivalent to x^2+y^2 = 16 after you divide everything by 4
Looking at the graph, the smallest x can be is -4. The largest x can be is 4. So the domain in interval notation is
![[-4,4]](https://tex.z-dn.net/?f=%5B-4%2C4%5D)
Similarly the range in interval notation is also <span>
![[-4,4]](https://tex.z-dn.net/?f=%5B-4%2C4%5D)
because the lowest you can go is y = -4. The highest you can go is y = 4</span>
Answer:
Hope this helps
Step-by-step explanation:
a) x^2 + 3x = x(x+3)
b) 2x^2 - 8x = 2x(x - 4)
c) 6x + 9x^3 = 3x(2 + 3x^2)
d) 12x^3 - 4x^2 = 4x^2(3x - 1)