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mash [69]
3 years ago
6

A warehouse worker moved 108 pallets in 4.5 hours. In minutes, what is the rate to move one pallet? The worker will be off the c

lock in 2 hours. How many pallets can he move before quitting time?
Mathematics
2 answers:
klasskru [66]3 years ago
6 0

Number of pallets moved in 4.5 hours = 108

converting 4.5 hours in minutes we get,

4*60 + 0.5*60 = 240+30 = 270 minutes

So, 108 pallets were moved in = 270 minutes

1 pallet was moved in = \frac{270}{108}=2.5 minutes

As the tie will get over in 2 hours or 2*60 = 120 minutes, the number of pallets that can be moved will be = \frac{120}{2.5}= 48 pallets.

Hence, 48 pallets can be moved before quitting time.

ZanzabumX [31]3 years ago
6 0

Answer:

The answer is 2.5 minutes; 48 pallets

Step-by-step explanation:

Number of pallets worker moved in a warehouse = 108

Number of hours it takes to do so  = 4.5

Rate at which they require to move one pallet is given by

Number of pallets worker moved in a warehouse = 108

Number of hours it takes to do so  = 4.5

Rate at which they require to move one pallet is given by

4.5/108 x 60 minutes = 2.5 minutes

Now, if the worker will be off the clock in 2 hours ,

So, number of pallets he can move before quitting time is given by

In 4.5 hours, number of pallets they moved = 108

In 1 hour, number of pallets they moved = 108/4.5 = 24

In 2 hours, number of pallets they moved = 24 x 2 = 48

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Answer:

a)  ∠A = 82.2° , ∠C = 62.8° , c =   17.01

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<u><em>Step(i)</em></u>:-

Given data ∠B measures 35° and the values of a and b are 19 and 11

∠B = 35° and sides a = 19 and b = 11

<em>By using sine rule </em>

<em></em>\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{Sin C}  = 2 R<em></em>

now we will use

\frac{a}{sin A} = \frac{b}{sin B}

\frac{19}{sin A} = \frac{11}{sin 35}

cross multiplication , we get

\frac{19 X sin 35}{11} = sinA

<em>sin A = 0.990</em>

<em>A = sin⁻¹( 0.990) = 82.2°</em>

<em> ∠A = 82.2°</em>

<u><em>Step(ii):-</em></u>

we know that ∠A +∠B +∠C = 180°

                         ∠C = 180° - ∠A -∠B

                          ∠C = 180° -82.2°-35°

                          ∠C = 62.8°

<u><em>Step(iii)</em></u>:-

<em>we will use formula</em>

<em></em>\frac{b}{sin B} = \frac{c}{Sin C}<em></em>

<em></em>\frac{11}{sin 35} = \frac{c}{Sin 62.8}<em></em>

\frac{11 X sin (62.8)}{sin 35} = C

<em>c =   17.01</em>

<u><em>Final answer</em></u>:-

<em> ∠A = 82.2° , ∠C = 62.8° , c =   17.01</em>

                         

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