<h3>
Answer:</h3>
will always be negative if is a negative number.
<h3>Explanation:</h3>
Because the sum of two negative numbers are always negative.
You would assume that in this figure, the number of colored sections with which are not colored with respect to a " touching " colored section, would be half of the total colored sections. However that is not the case, the sections are not alternating as they still meet at a common point. After all, it notes no two touching sections, not adjacent sections. Their is no equation to calculate this requirement with respect to the total number of sections.
Let's say that we take one triangle as the starting. This triangle will be the start of a chain of other triangles that have no two touching sections, specifically 7 triangles. If a square were to be this starting shape, there are 5 shapes that have no touching sections, 3 being a square, the other two triangles. This is presumably a lower value as a square occupies two times as much space, but it also depends on the positioning. Therefore, the least number of colored sections you can color in the sections meeting the given requirement, is 5 sections for this first figure.
Respectively the solution for this second figure is 5 sections as well.
The answer is the ratio of A's to the number of classes is 7 to 4. That's false. For the statement to be true the ratio should have been 4 to 7.
Answer:
Step-by-step explanation:
First, we need to write the polynomial in descending order
Then, grab the term with the highest power from the polynomial and divide it by the term with highest power from the polynomial located at the other side of the division symbol (this polynomial would be x^2+5x+8)
The result (x^3 / x^2) = x
This term will be part of the solution, and will be use to start the process of division.
This process start with the previous obtained term (x), which will be multiplied by the polynomial from the other side of the division symbol (x^2+5x+8).
The result another is another polynomial
This new polynomial will be multiply by negative 1
The new polynomial is then added to the poly (x^3+3x^2-4x-12)
The result will constitute a new poly, that will be use as the remaining of the division.
Since, our reamining differs from zero, and we still have member to simplify, we repeat the step 1 using the remaining as the new poly that needs to be divided by (x^2+5x+8).
The attached picture explains the whole procedure.