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beks73 [17]
4 years ago
5

Which of the following are zero-dimensional, one-dimensional figures?

Mathematics
2 answers:
asambeis [7]4 years ago
8 0

zero-dimensional - point

one-dimensional figures - ray, segment, line

attashe74 [19]4 years ago
3 0
<h2>Answer:</h2>

zero-dimensional--

         A.  Point

one-dimensional figures--

         C.  Ray

          E. Segment

          F.  Line

<h2>Step-by-step explanation:</h2>
  • A zero dimensional model is one which has no dimensions.

i.e. it does not has  any height, width, volume , length etc.

Among the given options the zero-dimensional is:

      A.  Point

( Since a point has no dimensions it is just represented by a simple word location)

  • One-dimensional means that is has just one dimension and hence give information such as length, width or height.

( A model in one dimension can't have a volume or area)

Among the given examples the one-dimensional figures are:

              C. Ray

( Since, a ray is a line that is extend infinitely in one direction and has a starting point)

          E.  Segment

A segment is a line which is bound from both the side i.e. we may know a information about the length of the segment.

            F.  Line

Line is the collection of the points along a straight path.

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An old bone contains 80% of its original carbon-14. Use the half-life model to find the age of the bone. Find an equation equiva
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Answer:

An old bone contains 80% of its original carbon-14 in 1844.6479 years

Step-by-step explanation:

We know that

half life time of C-14 is 5730 years

so, h=5730

now, we can use formula

P(t)=P_0(\frac{1}{2})^{\frac{t}{h} }

we can plug back h

and we get

P(t)=P_0(\frac{1}{2})^{\frac{t}{5730} }

An old bone contains 80% of its original carbon-14

so,

P(t)=0.80Po

we can plug it and then we solve for t

0.80P_0=P_0(\frac{1}{2})^{\frac{t}{5730} }

0.80=(\frac{1}{2})^{\frac{t}{5730} }

\ln \left(0.8\right)=\ln \left(\left(\frac{1}{2}\right)^{\frac{t}{5730}}\right)

t=-\frac{5730\ln \left(0.8\right)}{\ln \left(2\right)}

t=1844.6479

So,

An old bone contains 80% of its original carbon-14 in 1844.6479 years


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