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goldfiish [28.3K]
3 years ago
15

Andrew is showing his work in simplifying (−5.7 + 2.2) − 1.1.

Mathematics
1 answer:
sammy [17]3 years ago
5 0

Step 2 i believe im not sure tho.

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PLEASE HELP ME !!!
vfiekz [6]

Answer:

-0.4 or 2.3

Step-by-step explanation:

simple

each box is 0.1 unit

7 0
3 years ago
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Help me pls I kind of confused
Sunny_sXe [5.5K]
Ok so basically you have to anahajahabdbnxnxkskalakand
4 0
3 years ago
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Which pair of complex numbers has a real-number product? (1 + 3i)(6i) (1 + 3i)(2 – 3i) (1 + 3i)(1 – 3i) (1 + 3i)(3i)
Kobotan [32]

Answer:

<h2>(1 + 3i)(1 – 3i) gives real number product</h2>

Step-by-step explanation:

Given the expressions

(1 + 3i)(6i) ,(1 + 3i)(2 -3i), (1 + 3i)(1 - 3i), (1 + 3i)(3i)

From analysis one of the following pairs has real-number products

(1 + 3i)(2 -3i), (1 + 3i)(1 - 3i)

Performing operations on

(1 + 3i)(2 -3i)= 2-3i+6-6i^2 \\= 2-3i+6-6(-1) \\=2-3i+6+6 \\=14-3i

Performing operations on

(1 + 3i)(1 - 3i) \\= 1-3i+3i-9(i)^2 \\= 1+0-9(-1) \\= 1+9=10

6 0
3 years ago
Use the tables to find (fog)(5)
padilas [110]
7

Hope this helps


Mark brainliest please
8 0
2 years ago
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Determine X and Y<br>(2+i) (x+yi) = -7+3i​
IrinaK [193]

Answer:

x=-11\5+13\5i-iy

y=ix+(13\5+11\5i)

Step-by-step explanation:

x+yi=-7+3i\2+i

x+yi=\frac{\left(-7+3i\right)\left(2-i\right)}{\left(2+i\right)\left(2-i\right)}

x+yi=-11\5+13\5i

x=-11\5+13\5i-yi

x=-11\5+13\5i-iy

x+yi=\frac{-7+3i}{2+i}

x+yi=\frac{\left(-7+3i\right)\left(2-i\right)}{\left(2+i\right)\left(2-i\right)}

x+yi=\frac{-11+13i}{5}

x+yi=-\frac{11}{5}+\frac{13}{5}i

yi=-\frac{11}{5}+\frac{13}{5}i-x

\frac{iy}{i}=\frac{-\frac{11}{5}+\frac{13}{5}i-x}{i}

y=\frac{-\frac{11}{5}+\frac{13}{5}i-x}{i}

7 0
3 years ago
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