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Alja [10]
4 years ago
8

Which expression is equivalent to 4” x 4-5? A 412 B) 42 C 4-2 D 4-35

Mathematics
1 answer:
kap26 [50]4 years ago
4 0
The answer is 4-2 the c one
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I need all three answer for an assignment
AfilCa [17]
This is false... you can get an easy example: (-2) + (10) = 10 - 2 = 8
7 0
3 years ago
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Find the value of 'x.<br> (2x - 3)<br> (3x - 2)°<br> 17<br> O 19<br> 0 90<br> 0 21
Korolek [52]

Answer:

Step-by-step explanation:

3x - 2 + 2x - 3= 90

5x - 5 = 90

5x = 95

x = 19

answer is b

6 0
3 years ago
Help me please I'm on a time limit
olga_2 [115]
The original price times the off price to get how much is the discount 3.25*0.25=0.8125 Subtract the discount from the original price 3.25-0.8125=2.4375=2.44 Or 3.25*0.75=2.4375=2.44
7 0
4 years ago
24<br> ,<br> Factor:<br> x²-9<br> A<br> (x + 3XX-3)<br> B<br> (x+3)2<br> с<br> (x-3)<br> (x+3)(x+3)
Katarina [22]

Answer:

(x-3)(x+3)

Step-by-step explanation:

We are given the expression \displaystyle \large{x^2-9}:—

To factor this expression, we have a formula for it which is <u>difference of two squares</u>:—

\displaystyle \large{a^2-b^2=(a+b)(a-b)}

You can also swap from \displaystyle \large{(a+b)(a-b)} to \displaystyle \large{(a-b)(a+b)} via multiplication property.

From the expression, factor using the formula above:—

\displaystyle \large{x^2-9=(x^2)-(3)^2}\\\displaystyle \large{x^2-9=(x-3)(x+3)}

Therefore, the factored expression is:—

\displaystyle \large{\boxed{(x-3)(x+3)}}

__________________________________________________________

If you have any questions regarding the problem or need clarification of my answer/explanation, do not hesitate to ask in comment!

5 0
2 years ago
The height distribution of NBA players follows a normal distribution with a mean of 79 inches and standard deviation of 3.5 inch
Shtirlitz [24]

Answer:

The probability will be "0.0111".

Step-by-step explanation:

The given values are:

Mean,

\mu = 79

Standard deviation,

\sigma = 3.5

Now,

⇒ \sigma\bar x = \frac{\sigma}{\sqrt n}

         =   \frac{3.5}{\sqrt 16}

         =0.875

⇒ P(\bar x > 81) = 1 - P(\bar x < 81)

So,

= 1 - P{\frac{(\bar x - \mu \bar x )}{ \sigma \bar x}  < \frac{(81 - 79) }{0.875} ]

= 1 - P(z < 2.2857)

= 0.0111

7 0
3 years ago
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