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natka813 [3]
3 years ago
10

You are thinking of using a t procedure to construct a 95% confidence interval for the mean of a population. You suspect the dis

tribution of the population is not Normal and may be skewed. Which of the following statements is CORRECT? a. You should not use the t procedure because the population does not have a
Normal distribution.
b. You may use the t procedure, provided your sample size is large, say at least 40. c. You may use the t procedure because it is robust to nonNormality.
Mathematics
1 answer:
bonufazy [111]3 years ago
5 0

this makes no sense sos im only 8 years old.

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Answer:

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Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

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So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

In this problem, we have that:

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0.1 = 1.96*\sqrt{\frac{0.5*0.5}{n}}

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\sqrt{n} = 9.8

(\sqrt{n})^{2} = (9.8)^{2}

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The minimum number of cities we need to contact is 96.

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