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lesantik [10]
3 years ago
15

Sherman goes golfing every 6^\text{th}6 th 6, start superscript, start text, t, h, end text, end superscript day and Brad goes g

olfing every 7^\text{th}7 th 7, start superscript, start text, t, h, end text, end superscript day. If Sherman and Brad both went golfing today, how many days until they will go golfing on the same day again
Mathematics
2 answers:
nydimaria [60]3 years ago
7 0

Answer:

In every 42 days,  Sherman and Brad will go golfing on the same day.

Step-by-step explanation:

Given:

Sherman goes golfing every 6th day.

Brad goes golfing every 7th day.

If they both went golfing today, we need to determine how many days unit they will go golfing on the same day again.

Solution:

In order to determine how many days unit Sherman and Brad will go golfing on the same day again, we will take least common multiple of 6 and 7.

To find least common multiple of 6 and 7, we will list out their multiples.

6=6,12,18,24,30,36,42

7=7,14,21,28,35,42

We find out that the least common multiple of 6 and 7 =42.

Thus, we can conclude that Sherman and Brad will go golfing on same days on every 42nd day after they meet..

Anvisha [2.4K]3 years ago
7 0

Answer:

42

Step-by-step explanation:

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Answer:

a) P(X

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

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P(X

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P(8 \leq X\leq 10) = P(\frac{8-8.89}{2.11} \leq Z< \frac{10-8.89}{2.11})=P(-0.422 \leq Z\leq 0.526)=P(Z

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z=\frac{x-\mu}{\sigma}

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-0.842=\frac{x-8.89}{2.11}

And if we solve for x we got:

x = 8.89 -0.842(2.11)=7.11

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Answer:

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