Answer:
journal entries to record the December transactions
1-Dec
Cash $10500 (debit)
Common Stock $10500 (credit)
1-Dec
Rent Expense $950 (debit)
Cash $950 (credit)
1-Dec
Prepaid Insurance $600 (debit)
Cash $600 (credit)
1-Dec
Equipment $3600 (debit)
Cash $3600 (credit)
5-Dec
Supplies Expense $300 (debit)
Accounts Payable $300 (credit)
15-Dec
Cash $7200 (debit)
Service Revenue $7200 (credit)
16-Dec
Accounts Receivable $5200 (debit)
Service Revenue $5200 (credit)
21-Dec
Cash $2400 (debit)
Accounts Receivable $2400 (credit)
23-Dec
Accounts Payable $170 (debit)
Cash $170 (credit)
28-Dec
Wages Expense $4480 (debit)
Cash $4480 (credit)
30-Dec
Dividends $200 (debit)
Cash $200 (credit)
Explanation:
The General Journal consists of Entries of Expenses, Capital Expenditures and Receipts and Payments in Cash.
Answer:
The correct answer is B
Explanation:
The journal entry which is to be recorded for the service revenue at the end of May is as follows:
Unearned Revenue A/c..............Dr $5,333
Service RevenueA/c...........Cr $5,333.
Working Note:
Revenue = Total amount × Number of months / Total months
where
Amount is $8,000
Number of months means at the end of May which is a 2nd month
Total months is 3 months (April, May and June)
= $8,000 × 2 / 3
= $5,333
The correct answer that would best complete the given statement above would be the first option: FORCE. <span>Phil</span><span> wanted the computer that Amy had, so he just took it. This is an example of distribution by force. Distribution by force often happens when someone is getting more if they have more power. This kind of distribution often leads to conflict. </span>
Answer:
Current price of the stock of Jameson company is $18.62. Therefore, the correct option is A
Explanation:
The formula of required rate of return is:
Required rate of return = Risk free rate + Beta × Market risk premium
= 4% + 1.15 × 5%
= 4% 5.75%
= 9.75%
Computation of current stock price is:
Current stock price = Expected dividend per share / (Required rate of return - Growth in dividend)
= (0.75 + [5.50% × 0.75] ) / (0.0975 - 0.055)
= 0.79125 / 0.0425
= $18.62
Answer:
Full question: <em>On their birthdays, employees at a large company are permitted to take a 60-minute lunch break instead of the usual 30 minutes. Data were obtained from 10 randomly selected company employees on the amount of time that each actually took for lunch on his or her birthday. The company wishes to investigate whether these data provide convincing evidence that the mean time is greater than 60 minutes. Of the following, which information would NOT be expected to be a part of the process of correctly conducting a hypothesis test to investigate the question, at the 0.05 level of significance?</em>
<em>Answe</em><em>r: Since that the p-value is greater than 0.05, rejecting the null hypothesis and concluding that the mean time was not greater than 60 minutes. </em>
Explanation:
<em>From the given question let us recall the following statements:</em>
<em>Employees at a large company are permitted to take a 60-minute Lunch break instead of the 30 minutes.</em>
<em>Data was gotten from = 10 randomly selected company employees on the amount of time that each actually took for lunch on his or her birthday</em>
<em>Given that the p-value is greater than 0.05, rejecting the null hypothesis and concluding that the mean time was not greater than 60 minutes.</em>
<em>The company tries to investigate the data to know that the mean is greater than 60 minutes</em>
<em>the next step is to find the process of correctly conducting a hypothesis test to investigate the question, at the 0.05 level of significance</em>
<em>Therefore,</em>
<em>Since that the p-value is greater than 0.05, rejecting the null hypothesis and concluding that the mean time was not greater than 60 minutes. </em>
<em>Or</em>
<em>The P-value> 0.05</em>
<em>The mean time is not greater than 60 minutes</em>
