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Anarel [89]
3 years ago
5

Angela’s average for six math tests is 87. On her first four tests she had scores of 93, 87, 82, and 86. On her last test, she s

cored 4 points lower than she did on her fifth test. What scores did Angela receive on her fifth and sixth tests? fifth test = 85; sixth test = 81 fifth test = 85; sixth test = 89 fifth test = 90; sixth test = 86 fifth test = 89; sixth test = 85
Mathematics
2 answers:
Vaselesa [24]3 years ago
8 0
87=(T1+T2+T3+T4+T+T6)/6
87=(93+87+82+86+x+(x-4))/6
87*6=93+87+82+86+2x-4
87*6=344+2x
178=2x
89=x implies 85, 89
irina1246 [14]3 years ago
6 0

Answer:

89 first test 85 sixth test

Step-by-step explanation:

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mihalych1998 [28]

Answer:

The slope of tangent at point (1,-2) is \frac{2}{3}.

Step-by-step explanation:

The given equation of ellipse is

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Differentiate both sides with respect to x.

\frac{d}{dx}(2x^2+xy+y^2)=\frac{d}{dx}(4)

\frac{d}{dx}(2x^2)\frac{d}{dx}(xy)+\frac{d}{dx}(y^2)=\frac{d}{dx}(4)

4x+x\frac{dy}{dx}+y+2y\frac{dy}{dx}=0

(4x+y)+(x+2y)\frac{dy}{dx}=0

\frac{dy}{dx}=-\frac{4x+y}{x+2y}

Calculate the value of \frac{dy}{dx} at (1,-2).

\frac{dy}{dx}_{(1,-2)}=-\frac{4(1)+(-2)}{(1)+2(-2)}

\frac{dy}{dx}_{(1,-2)}=-\frac{2}{-3}

\frac{dy}{dx}_{(1,-2)}=\frac{2}{3}

Therefore the slope of tangent at point (1,-2) is \frac{2}{3}.

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3 years ago
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Natasha2012 [34]
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Answer:

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The correct answer is C

Step-by-step explanation:

hopr it helps

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