X= 12(.7)^x(exponent)
x is the doll you are on. For example if your looking for the height of the height of the doll after the 12 in. one then x=2 and so on
AC and DB are the same length. Set the two to equal each other and solve for y.
9y + 1 = 8y +17
Subtract 8y from both sides:
y + 1 = 17
Subtract 1 from each side:
y = 16
Now you know Y you can find the the length of DB:
DB = 8y +17 = 8(16) +17 = 128 + 17 = 145
EB is half of DB:
EB = 145 / 2
EB = 72.5
4 (k+3) (k+) is the answer
Here,
let width(b)be x then,
length (l)=9cm+x
area =112 sq cm
now,
area of rectangle=l*b
or, 112=(9+x)x
or, 112=9x+x^2
or, 0=x^2+9x-112
or, 0=x^2+(16-7)x-112
or, 0=x^2+16x-7x-112
or, 0=x(x+16)-7(x+16)
or, 0=(x-7)(x+16)
either,
0=x-7
or,7=x
x=7cm
Or,
0=x+16
or, -16=x
x= -16[impossible,as distance is never negative] so,
x=7cm
therefore,length = 7cm + 9 cm = 16cm and width = 7cm.
;)
