Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDLcholesterol?
sample mean = x-bar = 4.7
ME = 1.96*15.6/sqrt(43) = 4.663
95% CI: 4.7 - 4.663 < u < 4.7 + 4.663
Answer:
Step-by-step explanation:
37.70
Answer:
Rate of change (slope) = -5
Step-by-step explanation:
Rate of change = (-5 -0) / (-2 - - 3) = -5/1 = -5
Step-by-step explanation:
We can call the original value x. In 2012, the painting's value was 1.05 x. In the beginning of 2013, the value was (1.05 x) * 0.98, and that increased to (1.05x) * 0.98 * 1.40 at the end of 2013. When we simplify, we get 1.4406 x as a value, and we know that this is equal to $52,640. We can write 1.4406x = 52640, and when we solve for x, we get x ≈ $36415.38. Hope this helps!
