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3 years ago

20 POINTS Can someone please explain what I did wrong?

Mathematics

1 answer:

mr_godi [17]3 years ago

3 0

Your diagram is correct.

I would have however written the Given as stated

Given :

XB≅XA≅AY≅YB ( If they are equidistant then they are all the same distance, thus the values will all be equal)

Prove:

<x≅<b≅<y≅<a (this is because a square is formed) < is angle

XM≅YM≅AM≅MB (The fact that the previous statements are true means that this is a square, if M is the midpoint than all these segments are equal)

MX≅MY

Im not sure what you did wrong besides maybe you didn't prove it well enough, everything is correct that you have written. I cant read the pen but it looks like you were missing a step.

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Account A: $300 monthly deposits, interest rate is 4.2%. Account B: $250 monthly deposits, interest rate is 5.1%. Which account

Elan Coil [88]

Answer:

Step-by-step explanation:

We have to determine the future value of the annuity to determine which account has a greater value

Future value = Amount x annuity factor

annuity factor = Annuity factor = {[(1+r)^n] - 1} / r

Account A = 300 x[ (1.042)^15 - 1 ] / 0.042 = $6097.14

Account B = 250 x[ (1.051)^15 - 1 ] / 0.051 = $5435,42

Account A will be greater

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3 years ago

6th grade math help me pleaseeee

spayn [35]

The answer is D , start from 2 and count to 8 and it gives you your answer

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3 years ago

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Angles α and β are the two acute angles in a right triangle. Use the relationship between sine and cosine to find the value of β

Dimas [21]

Answer:

From given relation the value of β is 37.5°

Step-by-step explanation:

Given as :

α and β are two acute angles of right triangle

Acute angle have measure less than 90°

Now given as :

$sin(\frac{x}{2} + 2x)$ = $cos(2x +\frac{3x}{2})$

Or, $cos(90° - (\frac{x}{2}+2x))$ = $cos(2x +\frac{3x}{2})$

SO, $(90° - (\frac{x}{2}+2x))$ = $2x+\frac{3x}{2}$

Or, 90° = $2x+\frac{3x}{2}$ + $\frac{x}{2}+2x$

or, 90° = $\frac{4x}{2}$ + 4x

Or, 90° = $\frac{12x}{2}$

So, x = $\frac{90}{6}$ = 15°

∴ $sin(\frac{x}{2} + 2x)$ = $sin(\frac{15}{2} + 30)$

So, $sin(\frac{x}{2} + 2x)$ = sin $\frac{75}{2}$

∴ The value of Ф_1 = $\frac{75}{2}$ = 37.5°

Similarly $cos(2x +\frac{3x}{2})$ = $cos(30 +\frac{45}{2})$

So ,The value of Ф_2 = $\frac{105}{2}$ = 52.5°

∵ β α

So, As 37.5°52.5°

∴ β = 37.5°

Hence From given relation the value of β is 37.5° Answer

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3 years ago

What is the range of the relation?

tia_tia [17]

The correct answer is (-2,1,2,8)

The range are the y- values

The explanation:

The range is the set of all second elements of ordered pairs (y-coordinates). Only the elements "used" by the relation or function constitute the range.

Hope this helped you :D

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3 years ago

5 + 3(2+6) ÷ 4 <br> can someone explain how to solve this

konstantin123 [22]

Answer: 4.5

Step-by-step explanation:

do the numbers that are in parentheses first which is 2+6=8 next is 5+3=8 then add both ur answers together then divide that by 4 which should equal 4.5

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