Question

An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if points A and D belong to the x−axis and m∠BAD=60degrees?

Answer 1

Answer:

the value of a, if points A and D belong to the x−axis and m∠BAD=60 degrees is 2/√3

Step-by-step explanation:

Trapezoid ABCD with height 2 unit contain Points A and D which may be A(-1,0) and D(5.0)

Vertex of parabola is the point where parabola crosses its axis

Let suppose A and D are two points then draw altitude on them CE where C is on AD

As height of altitude has been given that is 2 then

total angle = 180 degrees

m∠BAD=60 degrees

m∠CEA =180 - 60 -90

             = 30

then the value for  AE = 2/√3.

y=a(x+1)(x−5).

where  2/√3 is right of -1 and 2 unit above x-axis