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Nikolay [14]
3 years ago
13

A jet travels 560 miles in 5 hours at this rate how far could the jet fly in 8 hours? What is the rate of speed of the jet?

Mathematics
1 answer:
Andrews [41]3 years ago
5 0
Let's first figure out how much it flies in a hour,

560/5 = 112

8 x 112 = 896

(112 mph)
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Simplify u^2+3u/u^2-9<br> A.u/u-3, =/ -3, and u=/3<br> B. u/u-3, u=/-3
VashaNatasha [74]
  The correct answer is:  Answer choice:  [A]:
__________________________________________________________
→  "\frac{u}{u-3} " ;  " { u \neq ± 3 } " ; 

          →  or, write as:  " u / (u − 3) " ;  {" u ≠ 3 "}  AND:  {" u ≠ -3 "} ; 
__________________________________________________________
Explanation:
__________________________________________________________
 We are asked to simplify:
  
  \frac{(u^2+3u)}{(u^2-9)} ;  


Note that the "numerator" —which is:  "(u² + 3u)" — can be factored into:
                                                      →  " u(u + 3) " ;

And that the "denominator" —which is:  "(u² − 9)" — can be factored into:
                                                      →   "(u − 3) (u + 3)" ;
___________________________________________________________
Let us rewrite as:
___________________________________________________________

→    \frac{u(u+3)}{(u-3)(u+3)}  ;

___________________________________________________________

→  We can simplify by "canceling out" BOTH the "(u + 3)" values; in BOTH the "numerator" AND the "denominator" ;  since:

" \frac{(u+3)}{(u+3)} = 1 "  ;

→  And we have:
_________________________________________________________

→  " \frac{u}{u-3} " ;   that is:  " u / (u − 3) " ;  { u\neq 3 } .
                                                                                and:  { u\neq-3 } .

→ which is:  "Answer choice:  [A] " .
_________________________________________________________

NOTE:  The "denominator" cannot equal "0" ; since one cannot "divide by "0" ; 

and if the denominator is "(u − 3)" ;  the denominator equals "0" when "u = -3" ;  as such:

"u\neq3" ; 

→ Note:  To solve:  "u + 3 = 0" ; 

 Subtract "3" from each side of the equation; 

                       →  " u + 3 − 3 = 0 − 3 " ; 

                       → u =  -3 (when the "denominator" equals "0") ; 
 
                       → As such:  " u \neq -3 " ; 

Furthermore, consider the initial (unsimplified) given expression:

→  \frac{(u^2+3u)}{(u^2-9)} ;  

Note:  The denominator is:  "(u²  − 9)" . 

The "denominator" cannot be "0" ; because one cannot "divide" by "0" ; 

As such, solve for values of "u" when the "denominator" equals "0" ; that is:
_______________________________________________________ 

→  " u² − 9 = 0 " ; 

 →  Add "9" to each side of the equation ; 

 →  u² − 9 + 9 = 0 + 9 ; 

 →  u² = 9 ; 

Take the square root of each side of the equation; 
 to isolate "u" on one side of the equation; & to solve for ALL VALUES of "u" ; 

→ √(u²) = √9 ; 

→ | u | = 3 ; 

→  " u = 3" ; AND;  "u = -3 " ; 

We already have:  "u = -3" (a value at which the "denominator equals "0") ; 

We now have "u = 3" ; as a value at which the "denominator equals "0"); 

→ As such: " u\neq 3" ; "u \neq -3 " ;  

or, write as:  " { u \neq ± 3 } " .

_________________________________________________________
6 0
3 years ago
Can someone plz help me I don’t understand how to do this and I am really struggling with the online stuff
sweet [91]

Answer:

A

Step-by-step explanation:

x=6.28111...

100 x=628.111...

1000x=6281.111...

subtract

900x=5653

x=5653/900

density of iodine=785×5653/900≈4930.672222...

Here 2 is repeating .

3 0
3 years ago
What number is 1000 before 30,638
jolli1 [7]
The answer is 29,638
8 0
3 years ago
Read 2 more answers
98 PTS!<br> Can someone please help?
padilas [110]

Answer: -22


Step-by-step explanation:

In the first question, we can simplify 2√8 to 4√2, making it :

(√10 + 4√2)(√10 - 4√2)

When you FOIL, √10(√10) = 10, and 4√2 * -4√2 = -32. The others cancel each other out. So -32 + 10 = -22.



5 0
3 years ago
Read 2 more answers
HELP upvote brainliest Write the statement that would go in the empty box to complete the flow proof below.
Degger [83]
Here, ∠WVX = ∠WZY
& ∠W = ∠W  [ Reflexive Property ]

Triangles have the constant sum, so they would be: equal.
WVX + WXV + W = W + WZY + WYZ
WXY = WYZ   [ ∠WVX = ∠WZY ]

Now, As all the angles are equal, we conclude:
ΔXVW ≈ ΔYZW  [ By ASA Postulate ]

Hope this helps!
8 0
3 years ago
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