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Sedaia [141]
3 years ago
15

The equation shows the relationship between the amount of money (y) remaining in Leigh's money box and the number of months (X)

Mathematics
1 answer:
balu736 [363]3 years ago
4 0

Answer:

A. The first choice.

Step-by-step explanation:

Look at function 1.

Month 1 -----> $50

Month 2  ----> $40

The difference between month 2 and moin th 1 is 1 month.

The difference between $40 and $50 is -$10. In other words, in function 1, the amount, y, went down $10 in a month. The rate of change of function 1 is -$10/month.

Function 2

y = -9x + 60

The rate of change is the slope. The slope of function 2 is -9. In function 2, the amount of money changes -$9/per month.

Answer: A. The first choice.

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A(0,-4)
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600,000+2,000+500+40+7 in standard form
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3 0
3 years ago
1( m² + 15m + 56) = (____) (m+8)<br>2 a² +5ab + 6b²=(a +2b (_____)<br><br>pastor po ​
Nutka1998 [239]

Step-by-step explanation:

1.

{m}^{2}  + 15m + 56 = ( \:  \:  \:  \:  \: )(m + 8) \\ solution \\  \:  \: taking \: lhs \\   = {m}^{2}  + 15m + 5 \\   = {m}^{2}  + (7 + 8)m + 56 \\ \:  \:  \: \:    = {m}^{2}  + 8m + 7m + 56 \:  \:  \\ now \: taking \: common \: factor \\  m(m + 8) + 7(m + 8) \\ (m + 7)(m + 8) \\ now \\  {m}^{2}  + 15m + 56 = (m + 7)(m + 8)

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{a}^{2}  + 5ab +  6 {b}^{2} = ( a + 2b)( \:  \:  \:  \:  \:  \:  \:  \: ) \\ solution \\ taking \:  \: lhs \\  =  {a}^{2}  + 5ab + 6 {b}^{2} \\ =  {a}^{2}  + ( 3+ 2)ab + 6 {b}^{2} \\  =  {a}^{2}  + 3ab + 2ab + 6 {b}^{2}  \\now \: taking \: common \: factor \\ a(a + 3b) + 2b(a + 3) \\ (a + 2b)(a + 3) \\ now \\ {a}^{2}  + 5ab +  6 {b}^{2} = ( a + 2b)( a + 3) ans

this may help you(:

7 0
2 years ago
Enter the missing numbers in the boxes to complete the table of equivalent ratios of time to distance.
andre [41]
Answer:  Here is the complete table, with the filled in values:
______________________________________________________________
Time (h)    Distance (mi)
    3                2 
    9                6
   12                8
   18               12
___________________________________________________

Explanation:
___________________________________________________
Let us begin by obtaining the "?" value; that is, the "distance" (in "mi.") ;
         when the time (in "h") is "18" ; 
___________________________________________________

12/8 = 18/?  

Note: "12/8 = (12÷4) / (8÷4) = 3/2 ;

Rewrite:  3/2 = 18/? ;  cross-multiply:  3*? = 2 * 18 ; 
                                                                        3*? = 36 ;

                                                                      Divide each side by "3" ;
                                                                            The "?" = 36/3 = 12 ;

So, 12/8 = 18/12 ;

The value: "12" takes the place for the "?" in the table for "distance (in "mi.);
                              when the "time" (in "h") is "18".
__________________________________________________________
Now, let us obtain the "? " value for the "distance" (in "mi.");
                when the "time" (in "h") is:  "9" .

12/8 = 9/? ;  Solve for "?" ;

We know (see aforementioned) that "12/8 = 3/2" ; 

So, we can rewrite:  3/2 = 9/? ;  Solve for "?" ; 

Cross-multiply:  3* ? = 2* 9 ;    3* ? = 18 ;  
                                                           Divide each side by "3" ;
                                                    to  get:  "6" for the "?" value.

When the time (in "h") is "9", the distance (in "mi.") is "6" .
____________________________________________________
Now, to solve the final "?" value in the table given.

9/6 = ?/2 ;  Note:  We get the "6" from our "calculated value" (see above problem). 

9/6 = (9÷3) / (6÷3) = 3/2 ;  

So, we know that the "?" value is:  "3" .

Alternately:   9/6 = ?/2 ; 

Cross-multiply:  6*? = 2*9 ;   6 * ? = 18 ;  Divide each side by "6" ;
                                                               to find the value for the "?" ; 
                                                                    "?" = 18/6 = "3" .

When the "distance" (in "mi.") is:  "2" ;  the time (in "h") is:  "3" .
____________________________________________________
Here is the complete table—with all the values filled in:
____________________________________________________

<span>Time (h)    Distance (mi)
____________________________________________________
    3                2 
    9                6
   12                8
   18               12
____________________________________________________
</span>
6 0
3 years ago
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