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Leviafan [203]
3 years ago
14

Marianna has been adding $30 to her savings account every month. Which model could represent the money in Marianna’s savings acc

ount (y) after x months?

Mathematics
1 answer:
andrezito [222]3 years ago
5 0
I believe it is c correct me if I’m wrong
You might be interested in
Express 8 1/5% as a mixed number or a fraction
Alexxandr [17]

Answer:

41/5

Step-by-step explanation:

First we change the 8 and 1/5% to 8.2%

Write the fraction down as a number over one = 8.2/1

Multiply both top and bottom by 10 for every number after the decimal point:

As we have 1 numbers after the decimal point, we multiply both numerator and denominator by 10. So,

8.2/1 = (8.2 × 10)

(1 × 10) = 82/10

Reduce the above fraction by dividing both numerator and denominator by the GCD (Greatest Common Divisor) between them. In this case, GCD (82,10) = 2. So, (82÷2)/(10÷2) = 41/5 when reduced to the simplest form.

As the numerator is greater than the denominator, we have an IMPROPER fraction, so we can also express it as a MIXED NUMBER, thus 82/10 is also equal to 81/5 when expressed as a mixed number.

7 0
2 years ago
Write the word sentence as an equation <br> 4less than n is-15
VikaD [51]

<u>4 less than n is -15</u>

<u>four is less than -15</u>

4<15

4 0
2 years ago
According to the Ruler Postulate, what does the set of points on any line correspond to?
Brrunno [24]

Answer:

Points on the Real number line correspond to Real numbers.The distance between two points is the absolute value of the difference of the corresponding numbers. ... The set of points on any line corresponds to the coordinate .

Step-by-step explanation:

Please mark brainliest and have a great day!

6 0
2 years ago
A pool measuring 8 meters by 26 meters is surrounded by a path of uniform​ width, as shown in the figure. If the area of the poo
Ainat [17]
Let the width path be x.
Length of the outer rectangle = 26 + 2x.
Width of the outer rectangle = 8 +2x.

Combined Area = (2x + 26)*(2x + 8) = 1008

2x*(2x + 8) + 26*(2x + 8 ) = 1008

4x² + 16x + 52x + 208 = 1008

4x² + 68x + 208 - 1008 = 0
4x² + 68x - 800 = 0.          Divide through by 4.
x²  + 17x - 200 = 0 . This is a quadratic equation.

Multiply first and last coefficients:  1*-200 = -200

We look for two numbers that multiply to give -200, and add to give +17

Those two numbers are 25 and -8.

Check:   25*-8 = -200         25 + -8 = 17

We replace the middle term of +17x in the quadratic expression with 25x -8x


 x² +17x - 200 = 0     

x² + 25x - 8x - 200 = 0     

x(x + 25) - 8(x + 25) = 0

(x+25)(x -8) = 0

x + 25 = 0    or   x - 8 = 0

x = 0 -25              x = 0 + 8

x = -25                    x = 8

The width of the path can not be negative.

The only valid solution is x = 8.

The width of the path is 8 meters.
8 0
2 years ago
D) A certain production process takes two stages 1 and 2. In a given period 5,000 units were introduced in process one and the c
Flauer [41]

The cost per unit of the complete units assuming that defective units are sold at Ksh 20 per unit is Rm 93.73.

<h3>What is the cost per unit with defective units?</h3>

The cost per unit with defective units can be computed by subtracting the sales value of the sold defective units from the total production costs, thereby reducing the total production costs, and then dividing the resulting figure by the number of good units.

<h3>Data and Calculations:</h3>

                               Process 1              Process 2          Total costs  

Materials             Rm 100,000              150,000              250,000

Labor                          50,000                50,000              100,000

Overheads                 50,000                20,000                70,000

Total costs                                                                        420,000

Input units = 5,000

Output units = 4,480

Defective units = 520 (5,000 - 4,480)

Sales revenue from defective units = Rm 104 (520 x Rm 0.20)

Cost per unit = Rm 93.73 (Rm 420,000 - Rm 104)/4,480

Thus, the cost per unit of the complete units assuming that defective units are sold at Ksh 20 per unit is Rm 93.73.

Learn more about accounting for defective units at brainly.com/question/10035226

#SPJ1

3 0
1 year ago
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