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2 years ago

If 2x - 5= 7x + 3, then x = ?

Mathematics

2 answers:

Leona [35]2 years ago

3 0

Answer: -8/5= x

Step-by-step explanation:

2x-5=7x+3

-5=5x+3

-8=5x

-8/5=x

SVEN [57.7K]2 years ago

3 0

Answer:

x=-8/5

Step-by-step explanation:

2x-5=7x+3

2x-7x=3+5

-5x=8

x=-8/5

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The slope of the line whose equation is x-3y= 1 is 0-3 -1/3 0 0 1/3

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x-3y= 1

The equation needs to be rewritten in proper Slope intercept form ( y = mx+b) where m is the slope and b is the y-intercept.

x-3y = 1

Subtract x from each side:

-3y = 1-x

Divide both sides by -3:

y = 1/-3 - x/-3

Simplify:

y = 1/3x - 1/3

The slope is 1/3

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Nat2105 [25]

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distributive property

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The coordinates of the vertices of a rectangle are (−3, 4) , (7, 2) , (6, −3) , and (−4, −1) . What is the perimeter of the rect

ki77a [65]

Answrer

Find out the what is the perimeter of the rectangle .

To prove

Now as shown in the figure.

Name the coordinates as.

A(−3, 4) ,B (7, 2) , C(6, −3) , and D(−4, −1) .

In rectangle opposite sides are equal.

Thus

AB = DC

AD = BC

Formula

$Disatnce\ formula = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2}}$

Now the points A(−3, 4) and B(7, 2)

$AB = \sqrt{(7- (-3))^{2} +(2- 4)^{2}}$

$AB = \sqrt{(10)^{2} +(-2)^{2}}$

$AB = \sqrt{100+4}$

$AB = \sqrt{104}$

$AB = 2\sqrt{26}\units$

Thus

$CD= 2\sqrt{26}\units$

Now the points

A (−3, 4) , D (−4, −1)

$AD = \sqrt{(-4 - (-3))^{2} +(-1- 4)^{2}}$

$AD = \sqrt{(-1)^{2} +(-5)^{2}}$

$AD = \sqrt{1 + 25}$

$AD = \sqrt{26}\units$

Thus

$BC = \sqrt{26}\units$

Formula

Perimeter of rectangle = 2 (Length + Breadth)

Here

$Length = 2\sqrt{26}\ units$

$Breadth = \sqrt{26}\ units$

$Perimeter\ of\ rectangle = 2(2\sqrt{26} +\sqrt{26})$

$Perimeter\ of\ rectangle = 2(3\sqrt{26})$

$Perimeter\ of\ rectangle = 6\sqrt{26}$

$\sqrt{26} = 5.1 (Approx)$

$Perimeter\ of\ rectangle = 6\times 5.1$

Perimeter of a rectangle = 30.6 units.

Therefore the perimeter of a rectangle is 30.6 units.

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-5(x + 2) + 5(x - 5)

creativ13 [48]

Answer:

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Step-by-step explanation:

X's cancel out each other

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