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JulijaS [17]
3 years ago
6

If 2x - 5= 7x + 3, then x = ?

Mathematics
2 answers:
Leona [35]3 years ago
3 0

Answer: -8/5= x

Step-by-step explanation:

2x-5=7x+3

-5=5x+3

-8=5x

-8/5=x

SVEN [57.7K]3 years ago
3 0

Answer:

x=-8/5

Step-by-step explanation:

2x-5=7x+3

2x-7x=3+5

-5x=8

x=-8/5

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kifflom [539]

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Step-by-step explanation:

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7 0
2 years ago
I need you to answer with a, b, c, d
solong [7]

To find the zeros of a quadratic fiunction given the equation you can use the next quadratic formula after equal the function to 0:

\begin{gathered} ax^2+bx+c=0 \\  \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}

For the given function:

f(x)=2x^2-10x-3x=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(2)(-3)}}{2(2)}x=\frac{10\pm\sqrt[]{100+24}}{4}\begin{gathered} x=\frac{10\pm\sqrt[]{124}}{4} \\  \\ x=\frac{10\pm\sqrt[]{2\cdot2\cdot31}}{4} \\  \\ x=\frac{10\pm\sqrt[]{2^2\cdot31}}{4} \\  \\ x=\frac{10\pm2\sqrt[]{31}}{4} \\  \end{gathered}\begin{gathered} x_1=\frac{10}{4}+\frac{2\sqrt[]{31}}{4} \\  \\ x_1=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \end{gathered}\begin{gathered} x_2=\frac{10}{4}-\frac{2\sqrt[]{31}}{4} \\  \\ x_2=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}

Then, the zeros of the given quadratic function are:

\begin{gathered} x=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \\  \\ x_{}=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}

Answer: Third option

8 0
1 year ago
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Answer:

Step-by-step explanation:

7 0
3 years ago
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irga5000 [103]

9514 1404 393

Answer:

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Step-by-step explanation:

There are several different forms of the equation for a line. Each is useful in its own way. Here, the line crosses the y-axis at a point between integer values, so using that intercept point could be problematical. That suggests the "point-slope" form of the equation for a line would be a better choice.

That form is ...

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The slope is given by the formula ...

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Using the first point, the equation for the line can now be written as ...

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8 0
2 years ago
Which fractions are equivalent to 4/5 and 2/7
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Answer: b

Step-by-step explanation:

5 0
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