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3 years ago

12

Which story problems could be solved using the given equation?

2 answers:

baherus [9]3 years ago

6 0

The coorect answer is Bo is carrying a bag of topsoil that is 78 full. He drops the bag and 13 of the soil pours out onto the ground. How much of the bag of soil poured onto the ground?

vladimir1956 [14]3 years ago

3 0

I think the correct answers are A, and C because you have to multiply to find the answers. The others will divide to find the answers.

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The rectangle below has an area of x^2-15x+56x square meters and a length of x-7 meters.

Gennadij [26K]

$Heya \: \: ! \\ \\ \\ Area \: of \: rectangle \: = Length \: \times Width \\ \\ We \: are \: given \: that \: , \\ \\ Length \: = \: \: ( \: x - 7 \: ) \: metres \\ Area \: \: \: \: \: = \: \: \: ( \: {x}^{2} - 15x + 56 \: ) \: square \: meters \\ \\ Therefore \: \: , \: \\ {x}^{2} - 15x + 56 = ( \: x - 7) \times Width \\ \\ Width = \frac{ ({x}^{2} - 15x + 56 )}{(x - 7)} \\ \\ Width = \frac{(x - 7)(x - 8)}{(x - 7)} \\ \\ \\ Width = ( \: x - 8 \: ) \: \: m \: \: \: \: \: \: \: \: \: Ans.$

3 0

3 years ago

Hannah’s favorite toy character is sold wearing one of many outfits. An outfit consists of one shirt, one pair of pants, and one

Serggg [28]

There is a 1/6 probability

8 0

3 years ago

6) Given the midpoint of segment KL ISM endpoint K ? (1, - 1)(8, - 7) . What are the coordinates of the other

Rudik [331]

Answer:

Step-by-step explanation:

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3 0

3 years ago

Find y'' if y= 9csc x

sineoko [7]

Answer:

y" = csc(x)[9cot²(x) - csc²(x)]

Step-by-step explanation:

Step 1: Define

y = 9csc(x)

Step 2: Find 1st derivative

y' = -9csc(x)cot(x)

Step 3: Find 2nd derivative

y" = 9csc(x)cot(x)cot(x) + -csc(x)csc²(x)

y" = 9csc(x)cot²(x) - csc³(x)

y" = csc(x)[9cot²(x) - csc²(x)]

4 0

3 years ago

If a student is 65.0 in tall, what is her height in m? (2.54 cm = 1 inch)

spayn [35]

Answer:

Height of the student=1.651m

Step-by-step explanation:

Given: Height of a student= 65.0 inch.

To find: Height of a student in meters.

Solution:

We know that 1 inch=2.54 cm, then

65.0 inch will be = $2.54{\times}65.0$

65.0 inch will be= $165.2 cm$

Also, we know that 1cm= $\frac{1}{100} m$ , then

165.2 cm will be equal to= $\frac{1}{100}{\times}165.1$

165.2 cm will be equal to= $1.651 meters$

Therefore, the height of a student in meters will be 1.651 meters.

5 0

3 years ago