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elena-s [515]
3 years ago
12

Which story problems could be solved using the given equation?

Mathematics
2 answers:
baherus [9]3 years ago
6 0

The coorect answer is Bo is carrying a bag of topsoil that is 78 full. He drops the bag and 13 of the soil pours out onto the ground. How much of the bag of soil poured onto the ground?

vladimir1956 [14]3 years ago
3 0
I think the correct answers are A, and C because you have to multiply to find the answers. The others will divide to find the answers.
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Find The Area of triangle ABC
Sergeeva-Olga [200]

Answer:

b.  area = 18 square units

Step-by-step explanation:

area of a triangle = 1/2 * base * height

area = 1/2 (6+3) + (6-2)

area = 1/2 * 9 * 4

area = 18 square units

therefore the answer is b.

3 0
3 years ago
What is 1/6+1/2 in its simplest form?
Salsk061 [2.6K]
1/2. 1/6
1/2×3=3/6
3/6+1/6=4/6
4/6=2/3

2/3
6 0
3 years ago
Read 2 more answers
12 gallons of water fill a tank of 3/4 capacity if the tank is fill full how many half gallons bottles can be filled with water
Advocard [28]
If 12= 3/4, then 16=4/4 would be a full tank.

The question is asking how many half gallon bottles can be filled, if there’s 16 full gallons, you’d multiply 16 by 2, and get 32.

Your answer is 32 half gallons
6 0
3 years ago
PLS HELP ILL GIVE 50 POINTS
Sloan [31]

Answer:

CU = 117

Step-by-step explanation:

Since we have similar triangles, we can use proportions.  Put the small triangle sides over the large triangle side.

WC             WD

----------- = -------------

WU             WV

26               20

----------- = -------------

36x-1             110

Using cross products

26*110 = 20* (36x-1)

Distribute

2860 = 720x - 20

Add 20 to each side

2860+20 = 720x-20+20

2880 = 720x

Divide by 720

2880/720 = 720x/720

4=x

We need to find CU

CU = WU - WC

Substituting in what we know

CU = 36x-1 -26

Since we know x=4

      = 36*4 -1 -26

      144 - 27

      = 117

6 0
2 years ago
The Identity function i behaves just like the number 1. That is (F o i)=f and (i o g)= g
andrezito [222]

I'll denote the identity function by \mathrm{Id}. Then for any functions f with inverse f^{-1},

\begin{cases}f\circ\mathrm{Id}=f\\\mathrm{Id}\circ f=f\\f\circ f^{-1}=\mathrm{Id}\end{cases}

One important fact is that composition is associative, meaning for functions f,g,h, we have

(f\circ g)\circ h=f\circ(g\circ h)

So given

h=f\circ g

we can compose the functions on either side with g^{-1}:

h\circ g^{-1}=(f\circ g)\circ g^{-1}=f\circ(g\circ g^{-1})

then apply the rules listed above:

h\circ g^{-1}=f\circ\mathrm{Id}=f

3 0
3 years ago
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