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Alina [70]
3 years ago
8

The graph of f(x) = x2 is shifted 3 units to the left to obtain the graph of g(x). Which of the following equations best describ

es g(x)?
g(x) = (x + 3)2
g(x) = x2 − 3
g(x) = x2 + 3
g(x) = (x − 3)2

Mathematics
1 answer:
ANTONII [103]3 years ago
6 0

Answer:

g(x) = (x + 3)^2

Step-by-step explanation:

When a function is shifted to the left or right we can think of a change of units, like a new independent variable is used.

If we have a quadratic function

f(x)=x^2

and the graph is shifted 3 units to the left, then we can think of a new unit u that is:

g(x)=u^2

The vertix of this parabola, that happens for u=0, happens for x=-3, as the graph is shifted 3 units to the left.

Then, the relation between u and x is:

u-x=0-(-3)=3\\\\u=x+3

We can use this relation in the new graph and replace u as:

g(x)=(x+3)^2

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Select the property that is demonstrated by: 3+7=7+3
gizmo_the_mogwai [7]

Answer:

Commutative property of addition

Step-by-step explanation:

This is called the commutative property of addition which states that a + b = b + a. In this case, a = 3 and b = 7.

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3 years ago
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If it's 11:50 A.M. right now, what time will it be, in 25 minutes?
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The answer is 12:15 A.M.
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En la tienda de mascotas "Animalo-T", se desea elevar un elefante de 2,900 kg utilizando una elevadora hidráulica de plato grand
Korvikt [17]

Answer:

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

Step-by-step explanation:

Por el Principio de Pascal se conoce que el esfuerzo experimentado por el elefante es igual a la presión ejercida por el plato pequeño. Es decir:

\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}} (1)

Donde:

F_{1} - Fuerza experimentada por el elefante, medida en newtons.

F_{2} - Fuerza aplicada sobre el plato pequeño, medida en newtons.

A_{1} - Área del plato grande, medida en metros cuadrados.

A_{2} - Área del plato pequeño, medida en metros cuadrados.

La fuerza aplicada sobre el plato pequeño es:

F_{2} = \left(\frac{A_{2}}{A_{1}} \right)\cdot F_{1}

La fuerza experimentada por el elefante es su propio peso. Por otra parte, el área del plato es directamente proporcional al cuadrado de su diámetro. Es decir:

F_{2} = \left(\frac{D_{2}}{D_{1}} \right)^{2}\cdot m\cdot g (2)

Donde:

D_{1} - Diámetro del plato grande, medido en centímetros.

D_{2} - Diámetro del plato pequeño, medido en centímetros.

m - Masa del elefante, medida en kilogramos.

g - Aceleración gravitacional, medida en metros por segundo cuadrado.

Si sabemos que D_{1} = 0.75\,m, D_{2} = 0.13\,m, m = 2900\,kg y g = 9.807\,\frac{m}{s^{2}}, entonces la fuerza a aplicar al émbolo pequeño es:

F_{2} = \left(\frac{0.13\,m}{0.75\,m} \right)^{2}\cdot (2900\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

F_{2} = 854.473\,N

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

3 0
3 years ago
Drake buys a ring that costs $8,000, which depreciates at a rate of 9.5% per year.
Alex73 [517]

Answer:

$1129.93

Step-by-step explanation:

100 - 9.5 = 90.5

8000 - 90.5 = 7909.5

7909.5 ÷ 7 = 1129.93

i hope this helps

4 0
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So discount means taken off
we find 15% of 199 and subtract from 199
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'of' means multiply
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discount so 199-29.85=169.15
answer is $169.15
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