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kondaur [170]
3 years ago
7

Find the measure of ∠C if ∠A = 3 2 x + 20 ∠B = 7 2 x + 20 ∠C = 5 2 x + 40 ∠D = 3 2 x + 10 A) 65° B) 76° C) 95° D) 115°

Mathematics
2 answers:
VARVARA [1.3K]3 years ago
7 0

Answer: D) 115 deggrees




Rudiy273 years ago
5 0
The sum of the angles of a quadrilateral is 360°.
\left(\dfrac{3}{2}x+20\right)+\left(\dfrac{7}{2}x+20\right)+\left(\dfrac{5}{2}x+40\right)+\left(\dfrac{3}{2}x+10\right)=360\\\\9x+90=360\\\\x=\dfrac{270}{9}=30

Given that x=30, the measure of ∠C is
  ∠C = (5/2)×30 +40 = 115

The appropriate choice is ...
  D) 115°
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The domain of ​(f​g)(x) consists of the numbers x that are in the domains of both f and g.
Dovator [93]

The statement "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g" is FALSE.

Domain is the values of x in the function represented by y=f(x), for which y exists.

THe given statement is "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g".

Now we assume the g(x)=x+2 and f(x)=\frac{1}{x-6}

So here since g(x) is a polynomial function so it exists for all real x.

f(x)=\frac{1}{x-6}<em>  </em>does not exists when x=6, so the domain of f(x) is given by all real x except 6.

Now,

(fg)(x)=f(g(x))=f(x+2)=\frac{1}{(x+2)-6}=\frac{1}{x-4}

So now (fg)(x) does not exists when x=4, the domain of (fg)(x) consists of all real value of x except 4.

But domain of both f(x) and g(x) consists of the value x=4.

Hence the statement is not TRUE universarily.

Thus the given statement about the composition of function is FALSE.

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3 0
1 year ago
Erica solved the equation −5x − 25 = 78; her work is shown below. Identify the error and where it was made.
Svetlanka [38]
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2 years ago
Somebody help me this is on my final and I don’t wanna fail it please somebody help me
Radda [10]

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Step-by-step explanation:

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