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Mekhanik [1.2K]
3 years ago
8

Suzie just became a personal trainer and is finalizing her pricing plans. One plan is to charge $59 for the initial consultation

and then $86 per session. Another plan is to charge $63 for the consultation and $84 per session. Suzie realizes that the two plans have the same cost for a certain number of sessions. What is that cost? How many sessions is that?
Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
8 0

Answer:

2 sessions, $231

Step-by-step explanation:

Make an equation (let x represent the number of sessions)

59+86x=63+84x

Subtract 84x from both sides

59+2x=63

Subtract 59 from both sides

2x=4

Divide by 2

x=2

At 2 sessions they will be equal

To find the cost, substitute 2 in for x

59+86(2)=63+84(2)

59+172=63+168

231=231

So, at 2 sessions the plans will cost the same at $231

Hope this helps! :)

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A new Youth Sports Center is being built in Hadleyville. The perimeter of the rectangular playing field is 536  yards. The lengt
Aleksandr [31]

Answer:

W = 58 yards, L = 210 yards

Step-by-step explanation:

P = 2 (L + W)

L = 4w - 22

P = 2 (4W - 22 + W)

536 = 8W - 44 + 2W

536 = 10W - 44

10 W = 536 + 44

10W = 580

W = 58 yards

Since L = 4W - 22

L = 4 (58) - 22

L = 232 - 22

L = 210 yards

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3 years ago
4 divided by 457. Please list the steps
exis [7]
You find out how many times 4 goes into 4 and get 1 then you find out how many times 4 goes into 5 and get 1 but you subtract 5 minus 4 and get 1 then bring down the 7 to get 17 then find out how many times 4 goes into 17 which is 4 times because 4 times 4 is 16 and you do 17 minus 16 and get 1 then add a decimal and bring down the 1 to get 10 then find out how many times 4 goes into 10 and get 2 subtract and get 2 bring down the zero turn it into 0 then you get 20 then find out how many times 4 goes into 20 and get 5 and 4*5=20 so 20-20 is 0 so your answer is 114.25
5 0
3 years ago
Read 2 more answers
Evaluate the expression for the given value of x.<br> 6x + 7 for x = 2<br> The solution is
pav-90 [236]

Answer:

6x + 7

6 * 2

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Step-by-step explanation:

4 0
3 years ago
Please help me solve this problem ASAP
DiKsa [7]

\bold{\huge{\blue{\underline{ Solution }}}}

<h3><u>Given </u><u>:</u><u>-</u></h3>

  • <u>The </u><u>right </u><u>angled </u><u>below </u><u>is </u><u>formed </u><u>by </u><u>3</u><u> </u><u>squares </u><u>A</u><u>, </u><u> </u><u>B </u><u>and </u><u>C</u>
  • <u>The </u><u>area </u><u>of </u><u>square </u><u>B</u><u> </u><u>has </u><u>an </u><u>area </u><u>of </u><u>1</u><u>4</u><u>4</u><u> </u><u>inches </u><u>²</u>
  • <u>The </u><u>area </u><u>of </u><u>square </u><u>C </u><u>has </u><u>an </u><u>of </u><u>1</u><u>6</u><u>9</u><u> </u><u>inches </u><u>²</u>

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>area </u><u>of </u><u>square </u><u>A</u><u>? </u>

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u><u> </u></h3>

The right angled triangle is formed by 3 squares

<u>We </u><u>have</u><u>, </u>

  • Area of square B is 144 inches²
  • Area of square C is 169 inches²

<u>We </u><u>know </u><u>that</u><u>, </u>

\bold{ Area \: of \: square =  Side × Side }

Let the side of square B be x

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ 144 =  x × x }

\sf{ 144 =  x² }

\sf{ x = √144}

\bold{\red{ x = 12\: inches }}

Thus, The dimension of square B is 12 inches

<h3><u>Now, </u></h3>

Area of square C = 169 inches

Let the side of square C be y

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ 169 =  y × y }

\sf{ 169 =  y² }

\sf{ y = √169}

\bold{\green{ y = 13\: inches }}

Thus, The dimension of square C is 13 inches.

<h3><u>Now, </u></h3>

It is mentioned in the question that, the right angled triangle is formed by 3 squares

The dimensions of square be is x and y

Let the dimensions of square A be z

<h3><u>Therefore</u><u>, </u><u>By </u><u>using </u><u>Pythagoras </u><u>theorem</u><u>, </u></h3>

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<u>That </u><u>is</u><u>, </u>

\bold{\pink{ (Perpendicular)² + (Base)² = (Hypotenuse)² }}

<u>Here</u><u>, </u>

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  • Perpendicular = z
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<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ (z)² + (x)² = (y)² }

\sf{ (z)² + (12)² = (169)² }

\sf{ (z)² + 144 = 169}

\sf{ (z)² = 169 - 144 }

\sf{ (z)² = 25}

\bold{\blue{ z = 5 }}

Thus, The dimensions of square A is 5 inches

<h3><u>Therefore</u><u>,</u></h3>

Area of square

\sf{ = Side × Side }

\sf{ = 5 × 5  }

\bold{\orange{ = 25\: inches }}

Hence, The area of square A is 25 inches.

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2 years ago
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The inequality would be
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Since he gains proficiency on the exercises, the total number he gets correct has to be at least 70%.  This means the inequality would have the symbol greater than or equal to, as it cannot be less and have him gain proficiency.

He has already answered 1 question and answers q more; this gives us a total of q+1.  Since he gains proficiency, the cutoff was 70%; 70%=70/100=0.70.  This gives us the expression 0.70(q+1).

Our total inequality would then be 0.75q ≥ 0.70(q+1)
3 0
3 years ago
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