Assuming monthly payment of $250, which implies APR=0.01*12=0.12.
If it is different, please specify.
target P=20000,
A=250
n=to be determined such that P>=target P=20000
The annuity equation with given (monthly) payment is given by
P=250(P/A,i,n)
=A((1+i)^n-1)/(i(1+i)^n)
=250(1.01^n-1)/(0.01(1.01)^n)
=25000(1.01^n-1)/(1.01^n)
Solve for n by trial and error,
Rewrite
20000<=25000(1-1/1.01^n)
=>
1.01^n>=25000/20000=1.25
Take log on both sides,
n*log(1.01)>=log(5)
n>=log(5)/log(1.01)=161. 75
=> n=162 (next integer)
Check:
P=250(P/A,0.01,162)=250*(1.01^162-1)/(.01*1.01^162)=20012.56 ok.
Answer: One DVD is $12 and one book is $1
Step-by-step explanation:
Let the DVD be d and the book be b.
Case 1:
3d + 4b = $40.......(1)
Case 2:
1d + 6b = $18........... (2)
In this equations above, I intend to eliminate variable d, so I'm going to multiply the coefficient of d in (1) to multiply (2)
3 × (1d + 6b = 18)
3d + 18b = 54........ .(3)
Then, subtract (1) from (3)
3d + 18b = 54
- ( 3d + 4b = 40)
3d - 3d + 18b - 4b = 54 - 40
0 + 14b = 14
b = 14/14
b = 1.
Then substitute 1 for b in (2)
1d + 6(1) = 18
d + 6 = 18
d = 18 - 6
d = 12.
(d,b) = (12,1)
Answer:
eboi
Step-by-step explanation:
The value of the equation
