Answer:
Observational study.
Step-by-step explanation:
In an observational study, the data is calculated but there are no experiments to change anything.
In a designed experiment, an experiment is applied to a group of people and it's effects are studied.
In this problem, we have that:
Male and female college students give their total credit card debt. There are no experiments to change anything. So it is an observational study.
Answer:
7.2 inches far from the bed.
Step-by-step explanation:
4.8 ft = 57.6
72-57.6 = 14.4
Since there is 2 edges. Divide by 2.
14.4/2 = 7.2 inches.
5/8 = 0.625
3/4 = 0.75
1/2 = 0.5
9/16 = 0.5625
Least to Greatest
1/2, 9/16, 5/8, 3/4
Answer: the 59th term is -496.
Step-by-step explanation:
To find the amount of fencing needed, we will find tge perimeter
To find the perimeter;
Find the distance |AB|, |BC|, |CD| and |DA|
We will use the formula below to find the distances:
![|d|=\sqrt[]{(x_2-x_1)^2+(y_{2-}y_1)^2}](https://tex.z-dn.net/?f=%7Cd%7C%3D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_%7B2-%7Dy_1%29%5E2%7D)
Distance |AB|
A(7,7), B(16,7)
x₁=7 y₁=7 x₂=16 y₂=7
Substituting into the formula;
![|AB|=\sqrt[]{(16-7)^2+(7-7)^2}](https://tex.z-dn.net/?f=%7CAB%7C%3D%5Csqrt%5B%5D%7B%2816-7%29%5E2%2B%287-7%29%5E2%7D)
![=\sqrt[]{9^2+0}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B9%5E2%2B0%7D)
![=\sqrt[]{9}^2\text{ =9}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B9%7D%5E2%5Ctext%7B%20%3D9%7D)
Distance |BC|
B(16,7), C(2,2)
x₁=16 y₁=7 x₂=2 y₂=2
substituting into the formula;
![|BC|=\sqrt[]{(2-16)^2+(2-7)^2}](https://tex.z-dn.net/?f=%7CBC%7C%3D%5Csqrt%5B%5D%7B%282-16%29%5E2%2B%282-7%29%5E2%7D)
![=\sqrt[]{(-14)^2+(5)^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B%28-14%29%5E2%2B%285%29%5E2%7D)
![=\sqrt[]{196+25}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B196%2B25%7D)
![=\sqrt[]{221}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B221%7D)

Distance |CD|
C(2,2), D(16,2)
x₁=2 y₁=2 x₂=16 y₂=2
substituting into the formula;
![|CD|=\sqrt[]{(16-2)^2+(2-2)^2}](https://tex.z-dn.net/?f=%7CCD%7C%3D%5Csqrt%5B%5D%7B%2816-2%29%5E2%2B%282-2%29%5E2%7D)
![=\sqrt[]{14^2+0}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B14%5E2%2B0%7D)
![=\sqrt[]{14^2}=14](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B14%5E2%7D%3D14)
Distance |DA|
D(16,2) A(7,7)
x₁=16 y₁=2 x₂=7 y₂=7
Substituting into the formula;
![|DA|=\sqrt[]{(7-16)^2+(7-2)^2}](https://tex.z-dn.net/?f=%7CDA%7C%3D%5Csqrt%5B%5D%7B%287-16%29%5E2%2B%287-2%29%5E2%7D)
![=\sqrt[]{(-9)^2+(5)^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B%28-9%29%5E2%2B%285%29%5E2%7D)
![=\sqrt[]{81+25}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B81%2B25%7D)
![=\sqrt[]{106}=10.30](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B106%7D%3D10.30)
Perimeter = |AB|+|BC|+|CD|+|DA|
= 9 + 14.87 + 14 + 10.30
=48.17
≈48
Hence;
48 feet of fencing is needed