Ask question

Ask question

All categories

3 years ago

10

What is the total amount that first consumer bank revive after lending Jane $7,000 for three years at an interest rate of 5 perc

ent compounded annually

1 answer:

yKpoI14uk [10]3 years ago

8 0

Answer: $8103.38 because:
7000(1+.05)^3
Hope this helps!!!!!!

You might be interested in

Aaron has three slabs of beeswax. He plans to melt them and use all of the wax to form 36 candles. If all the candles are the sa

Anton [14]

Weight of slab of beeswax isn't given.

Assume slab of beeswax = 36 gram.

Answer:

3 gram

Step-by-step explanation:

Each slab of beeswax = 36 gram

Total weight of all 3 slabs = (3 * 36) = 108 g

Number of same-sized candles to make = 36

The weight of each candle will be ;

Total weight of slabs / number of candles

108 g / 36

= 3 grams

8 0

2 years ago

If 600 J of work is done in 3 s, what is the power? (Power: P = W/t) 0.005 W 200 W 603 W 1800 W

nikitadnepr [17]

B) 200W
Hope this helps amigo

5 0

2 years ago

Read 2 more answers

PLEASE HELP!!!!!!!!

Korolek [52]

Answer:

2π - 4√5

(= -2.66 to nearest hundredth).

Step-by-step explanation:

√(2π - 4√5)^2

= 2π - 4√5 (by the definition of a square root)

If you want an approximate value it is

-2.66 to the nearest hundredth

7 0

2 years ago

G^2 + 4gh; if g = -3 and h = 5

xxTIMURxx [149]

Answer:

Step-by-step explanation:

We know that g = -3 and h = 5

Plugging in the values for g and h you will get:

$g^{2} + 4gh$

$(-3)^{2} + 4(-3)(5)$

$9 + (-60)$

Final answer is $-51$

3 0

2 years ago

The number of accidents that occur at a busy intersection is Poisson distributed with a mean of 4.5 per week. Find the probabili

Mariana [72]

Answer:

a) 0.01111

b) 0.4679

c) 0.33747

Step-by-step explanation:

We are given the following in the question:

The number of accidents per week can be treated as a Poisson distribution.

Mean number of accidents per week = 4.5

$\lambda= 4.5$

Formula:

$P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}$

a) No accidents occur in one week.

$P(x =0)\\\\= \displaystyle\frac{4.5^0 e^{-4.5}}{0!}= 0.01111$

b) 5 or more accidents occur in a week.

$P( x \geq 5) = 1-\displaystyle \sum P(x$

c) One accident occurs today.

The mean number of accidents per day is given by

$\lambda = \dfrac{4.5}{7} = 0.64$

$P(x =1)\\\\= \displaystyle\frac{0.64^1 e^{-0.64}}{1!}= 0.33747$

5 0

2 years ago