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const2013 [10]
3 years ago
10

I really need help with this thank you​

Mathematics
2 answers:
eduard3 years ago
8 0

Answer:

The photo is not clear post a clear photo then i will see that

Levart [38]3 years ago
7 0

Answer:

per = 28 units

area 32 sq units

Step-by-step explanation:

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The mean age of 5 people in a room is 32 years. A person enters the room. The mean age is now 34. What is the age of the person
nikdorinn [45]
The age of the person is 36 :) hoped this helped
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Point M is the midpoint of segment AB. If AM = 50 – 3x and MB = –20 + 4x, find the value of AM
love history [14]
The answer to your question is 20
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Anarel [89]
10 is the missing number.
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3 years ago
Use substitution to write an equivalent quadiatic equation<br> ( 3x^2)^2+7(3x +2) -8=0
mezya [45]

Answer:

9x^4+21x+6=0

Step-by-step explanation:

( 3x^2)^2+7(3x +2) -8=0

((3^2)*(x^2)^2)+(7*3x)+(7*2)-8=0

9(x^4)+21x+14-8=0

9x^4+21x+6=0

7 0
3 years ago
James folds a piece of paper in half several times,each time unfolding the paper to count how many equal parts he sees. After fo
Snezhnost [94]

Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

The needed function is y = 2 ^n

Step-by-step explanation:

Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒  n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒  for n = 1 , y = 2       ..... (1)

Similarly, if the paper if folded TWICE  ⇒  n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒  for n = 2 , y = 4       ..... (2)

⇒y  = 2^2  =  2^n

Continuing the same way, if the paper is folded SEVEN times  ⇒  n = 7

So, y = 2^ n = 2^7 = 128

⇒  There are total 128 equal parts.

Lastly,  if the paper is folded ELEVEN  times  ⇒  n = 11

So, y = 2^ n = 2^{11} = 2048

⇒  There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

And the needed function is y = 2 ^n

8 0
4 years ago
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