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lions [1.4K]
4 years ago
5

Use properties of logarithms to condense the logarithmic expression below. Write the expression as a single logarithm whose coef

ficient is 1. Where possible, evaluate logarithmic expressions. 1/8 ln x + ln y 1/8 ln x + ln y = (Simplify your answer.) Use properties of logarithms to condense the logarithmic expression. Write the expression as a single logarithm whose coefficient is 1. Evaluate logarithmic expressions if possible. 2 ln(x + 7) - 9 ln x 2 ln(x + 7) - 9 ln x =
Mathematics
1 answer:
yKpoI14uk [10]4 years ago
3 0

Answer:

(a) \ln (x^{\frac{1}{8}}y)

(b) \ln (\dfrac{(x+7)^2}{x^9})

Step-by-step explanation:

The given expression is

\frac{1}{8}\ln x+\ln y

Using the properties of logarithm we get

\ln (x^{\frac{1}{8}})+\ln y              [\because \ln a^b=b\ln a]

\ln (x^{\frac{1}{8}}y)              [\because \ln(ab)=\ln a+\ln b]

Therefore, the simplified form of given expression is \ln (x^{\frac{1}{8}}y).

The given expression is

2\ln (x+7)-9\ln x

Using the properties of logarithm we get

\ln (x+7)^2-\ln x^9              [\because \ln a^b=b\ln a]

\ln (\dfrac{(x+7)^2}{x^9})       [\because \ln(\frac{a}{b})=\ln a-\ln b]

Therefore, the simplified form of given expression is \ln (\dfrac{(x+7)^2}{x^9}).

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The line segment that connects the two vertices of a hyperbola is called the ____ axis.
liubo4ka [24]

Answer:

A. Transverse.

Step-by-step explanation:

We have been given a statement and we are supposed to choose the correct option to fill in the blank for our given statement.

Statement: The line segment that connects the two vertices of a hyperbola is called the ____ axis.

Since we know that the endpoints of transverse axis are known as the vertices of hyperbola, so the line segment that connects the two vertices of a hyperbola is called the <u>transverse </u> axis.

Therefore, option A is the correct choice.

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3 years ago
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kifflom [539]

Answer:

65

Step-by-step explanation:

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Fill in each blank so that the resulting statements are true.The vertices of The foci are located at ____.
stealth61 [152]

Given equation is

\frac{x^2}{9}-\frac{y^2}{16}=1

It can be written as follows.

\frac{x^2}{3^2}-\frac{y^2}{4^2}=1

Which is of the form

\frac{x^2}{a^2}-\frac{y^2}{b^2}=1

where a=3 and b=4.

We know that the coordinates of the vertices are (a,0) and (-a,0)

Substitute a=3, we get

The vertices are (3,0) and (-3,0).

We know that the coordinates of the foci are (c,0) and (-c,0)

c=\sqrt[]{a^2+b^2}

Substitute a=3 and b=4, we get

c=\sqrt[]{3^2+4^2}=\sqrt[]{9+16}=\sqrt[]{25}=5

Substitute c=5, we get

Hence the foci are (5,0) and (-5,0).

5 0
1 year ago
.12 divided by 7.15 please put step by step thank you
wel

Answer:

59.58333

Step-by-step explanation:

715/12

write in long division format ( which u did )

divide 71 by 12 to get 5

multiply 71 by 12 = 5

subtract 60 by 71

bring down the next number

115/12 =9

multiply 12 by 9

subtract 180 by 115

add a decimal on the top and bring down zero

divide 70 by 12 = 5

multiply 5 by 12

subtract 60 - 70

bring down a zero

divide 100 by 12 = 8

multiply 12 by 8

subtract 96 by 100

bring down zero

divide 40 by 12 = 3

anddd u get the point

sorry it took so long

5 0
3 years ago
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