What is equivalent to (x+y+2) (y+1)

Jason is drawing a blueprint of his bedroom for his new house. Using a scale of 1 inch = 3.5 feet, he drew his bedroom 3 inches

svetoff [14.1K]

The approximate area will be 128.63 ( or 128.625 ) feet squared

4 0

3 years ago

An athlete pays 1/10 of her annual income to her agent.The agent pays 2/9 of that money to his assistant.What fraction of her an

Anon25 [30]

You multiply the fractions like this:
1/10 * 2/9 = 2/90

Then you reduce it.

1/45

So 1/45 of the athlete's annual income is payed to the assistant. <span />

4 0

4 years ago

The price of a shirt is increased by 20%, and the price of a 40% pair of shoes is decreased by 40%. If the new price of the shir

nata0808 [166]

Answer:

Zadanie 5.

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czerwoną linią granice

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do pierwszych wystąpień

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email should be 50 to 120 words, not including

the words provided a

Imagine you've got a new British friend called

Joshua. Write an email to him. In your email:

• introduce yourself (age town, class at school)

describe your room or your favourite things

• describe your family and your best friend or

group of friends

000

To: Joshua

Subject: All about me!

Hi Joshua,

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6 0

3 years ago

Joe is training for a race in 30 days. He needs to run a total of 135 miles. How many miles will joe need to run each day to be

marin [14]

He needs to run 4.5 miles each day.

4 0

3 years ago

A national manufacturer of ball bearings is experimenting with two different processes for producing precision ball bearings. It

lapo4ka [179]

Answer:

A. As we are trying to test if the two processes yield different average errors, we are interested in any of the two posibilities: the average error of process A being statistically significant lower or bigger than the average error of Process B. That is why this is a two-tailed test.

B. t=-3.144

C. The critical value for a significance level of 0.05, a two tailed test with 4 degrees of freedom is t=±2.064.

D. P-value = 0.004

E. Reject H0

F. The probability of making a Type I error is equal to the significance level: P(Type I error) = 0.05.

Step-by-step explanation:

This is a hypothesis test for the difference between populations means.

The claim is that the two processes yield different average errors.

As we are trying to test if the two processes yield different average errors, we are interested in any of the two posibilities: the average error of process A being statistically significant lower or bigger than the average error of Process B. That is why this is a two-tailed test.

Then, the null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0$

being μ1: average error for Process A and μ2: average error fo Process B.

The significance level is 0.05.

The sample 1, of size n1=12 has a mean of 2 and a standard deviation of 1.

The sample 1, of size n1=14 has a mean of 3 and a standard deviation of 0.5.

The difference between sample means is Md=-1.

$M_d=M_1-M_2=2-3=-1$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{1^2}{12}+\dfrac{0.5^2}{14}}\\\\\\s_{M_d}=\sqrt{0.083+0.018}=\sqrt{0.101}=0.318$

Then, we can calculate the t-statistic as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{-1-0}{0.318}=\dfrac{-1}{0.318}=-3.144$

The degrees of freedom for this test are:

$df=n_1+n_2-1=12+14-2=24$

The critical value for a significance level of 0.05, a two tailed test with 4 degrees of freedom is t=±2.064.

This test is a two-tailed test, with 24 degrees of freedom and t=-3.144, so the P-value for this test is calculated as (using a t-table):

$P-value=2\cdot P(t$

As the P-value (0.004) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the two processes yield different average errors.

5 0

3 years ago