All categories

3 years ago

Which is an accurate conclution regarding the system of equations below ? Y=2/3x-1 and Y=3-2/3x

Mathematics

2 answers:

Svetlanka [38]3 years ago

4 0

Answer:

Lets start with the given system of linear equations In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa). So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 ...

Step-by-step explanation:

GREYUIT [131]3 years ago

4 0

Answer:25

Step-by-step explanation: gnfxnhhfcngn bhh fxbx

You might be interested in

13x12=[3x______]+[3x_____]+[10 x______]+[10x____]

Ray Of Light [21]

Answer:it's on the explanation

Step-by-step explanation:

3 x 1

10 x 5

10 x 9

6 0

4 years ago

Please help I am so lost!!!

ASHA 777 [7]

$\bf tan\left( \frac{x}{2} \right)+\cfrac{1}{tan\left( \frac{x}{2} \right)}\\\\
-----------------------------\\\\
tan\left(\cfrac{{{ \theta}}}{2}\right)=
\begin{cases}
\pm \sqrt{\cfrac{1-cos({{ \theta}})}{1+cos({{ \theta}})}}
\\ \quad \\

\cfrac{sin({{ \theta}})}{1+cos({{ \theta}})}
\\ \quad \\

\boxed{\cfrac{1-cos({{ \theta}})}{sin({{ \theta}})}}
\end{cases}\\\\$

$\bf -----------------------------\\\\
\cfrac{1-cos(x)}{sin(x)}+\cfrac{1}{\frac{1-cos(x)}{sin(x)}}\implies \cfrac{1-cos(x)}{sin(x)}+\cfrac{sin(x)}{1-cos(x)}
\\\\\\
\cfrac{[1-cos(x)]^2+sin^2(x)}{sin(x)[1-cos(x)]}\implies 
\cfrac{1-2cos(x)+\boxed{cos^2(x)+sin^2(x)}}{sin(x)[1-cos(x)]}
\\\\\\
\cfrac{1-2cos(x)+\boxed{1}}{sin(x)[1-cos(x)]}\implies \cfrac{2-2cos(x)}{sin(x)[1-cos(x)]}
\\\\\\
\cfrac{2[1-cos(x)]}{sin(x)[1-cos(x)]}\implies \cfrac{2}{sin(x)}\implies 2\cdot \cfrac{1}{sin(x)}\implies 2csc(x)$

4 0

3 years ago

keiko had 6 more red tiles than yellow tiles she gave half of her yellow tiles to ramon. if ramon has 7 yelliw tiles how many ti

kondor19780726 [428]

It would be 6.5 excuse if it was 14 it would be 7 but the other half would be 6.5

6 0

3 years ago

What is the inverse of y = 16x^2 + 1

tankabanditka [31]

X = 16y^2 + 1
x - 1 = 16y^2
(x - 1)/16 = y^ 2
( (x-1) / 16 ) ^1/2 = y
( (x-1) ^ 1/2 ) / 4 = y

4 0

4 years ago

Distributive property Use the distributive property to remove the parentheses .{y+10}12=

malfutka [58]

Answer:

12y + 120

Step-by-step explanation:

First of, what is the distributive property?

The distributive property is the property that helps distribute numbers under the parenthesis.

For example, lets use {x+1}4. You distribute the 4 towards the x and the one like this:

4(x) + 1(4)

4x + 4

Now, let's go back to your problem

Solution:

{y+10}12

12(y) +12(10)

= 12y + 120

Hope this helps! Make sure to give me the brainliest answer since it would be greatly appreciated! Thank You!

5 0

3 years ago

Read 2 more answers