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2 years ago

Need help with this explain

Mathematics

2 answers:

konstantin123 [22]2 years ago

5 0

12,500 divide 1999, 12,500 divide 1998, etc hope this helps

Savatey [412]2 years ago

4 0

For 1999 it would be 10625$

To calculate % decrease do, 100% - 15% = 85%
then; 85% divide 100 = 0.85

0.85 * 12500 (original price) = 10625$

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Determine whether each point appears on the line with the given slope and y−intercept. Select Yes or No for each point.

-Dominant- [34]

Could you put a graph plz??

6 0

3 years ago

Read 2 more answers

The regression equation y = -0.414x + 106.55 approximates the percent of people in an

murzikaleks [220]

The correct option will be: A. 67%

Explanation

Given equation is: $y = -0.414x + 106.55$ , where $x$ is the length of the film in minutes and $y$ is the percentage of people finish watching the film.

Here, the length of the documentary is given as 95 minutes. So, we will plug $x=95$ into the above equation and get....

$y=-0.414(95)+106.55\\ \\ y=-39.33+106.55\\ \\ y=67.22 \approx 67$

(Rounded to the nearest percent)

So, the percentage of people in an audience who will finish watching a documentary that is 95 minutes long will be 67%

4 0

3 years ago

1.) Find the length of the arc of the graph x^4 = y^6 from x = 1 to x = 8.

xxTIMURxx [149]

First, rewrite the equation so that y is a function of x :

$x^4 = y^6 \implies \left(x^4\right)^{1/6} = \left(y^6\right)^{1/6} \implies x^{4/6} = y^{6/6} \implies y = x^{2/3}$

(If you were to plot the actual curve, you would have both $y=x^{2/3}$ and $y=-x^{2/3}$ , but one curve is a reflection of the other, so the arc length for 1 ≤ x ≤ 8 would be the same on both curves. It doesn't matter which "half-curve" you choose to work with.)

The arc length is then given by the definite integral,

$\displaystyle \int_1^8 \sqrt{1 + \left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx$

We have

$y = x^{2/3} \implies \dfrac{\mathrm dy}{\mathrm dx} = \dfrac23x^{-1/3} \implies \left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2 = \dfrac49x^{-2/3}$

Then in the integral,

$\displaystyle \int_1^8 \sqrt{1 + \frac49x^{-2/3}}\,\mathrm dx = \int_1^8 \sqrt{\frac49x^{-2/3}}\sqrt{\frac94x^{2/3}+1}\,\mathrm dx = \int_1^8 \frac23x^{-1/3} \sqrt{\frac94x^{2/3}+1}\,\mathrm dx$

Substitute

$u = \dfrac94x^{2/3}+1 \text{ and } \mathrm du = \dfrac{18}{12}x^{-1/3}\,\mathrm dx = \dfrac32x^{-1/3}\,\mathrm dx$

This transforms the integral to

$\displaystyle \frac49 \int_{13/4}^{10} \sqrt{u}\,\mathrm du$

and computing it is trivial:

$\displaystyle \frac49 \int_{13/4}^{10} u^{1/2} \,\mathrm du = \frac49\cdot\frac23 u^{3/2}\bigg|_{13/4}^{10} = \frac8{27} \left(10^{3/2} - \left(\frac{13}4\right)^{3/2}\right)$

We can simplify this further to

$\displaystyle \frac8{27} \left(10\sqrt{10} - \frac{13\sqrt{13}}8\right) = \boxed{\frac{80\sqrt{10}-13\sqrt{13}}{27}}$

7 0

3 years ago

Can someone please help me this is geometry I don’t understand I have like more than an hour trying to figure this but I cancele

Aleks04 [339]

Answer:

5, last option

Step-by-step explanation:

Sides to be calculated are equal as both are opposite same angles, are adjacent to common hypotenuse of right triangles

3x+1=2x+6
x=6-1
x=5

6 0

3 years ago

213.49 in standard form

Travka [436]

Answer:

2.1349 x10^2

Step-by-step explanation:

i used a standard form calculator

7 0

2 years ago