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Leona [35]
3 years ago
9

Two sections of a class took the same quiz. Section A had 15 students who had a mean score of 80, and Section B had 20 students

who had a mean score of 90. Overall, what was the approximate mean score for all of the students on the quiz
Mathematics
1 answer:
Ksju [112]3 years ago
3 0

Answer:

86

Step-by-step explanation:

In this question, we are asked to calculate the average mean score for a group of students split into two different emerging groups.

We calculate the total score for each of the groups. This is done by multiplying the average score by the number of students.

Total score of section A is 15 * 80 = 1,200

For section B, total score is 20 * 90 = 1,800

Overall score is thus 1200 + 1800 = 3000

We add the scores together and divide by the total number of students in both sections

Average score is thus 3000/35 = 85.71 which is approximately 86

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Suppose that the data for analysis includes the attributeage. Theagevalues for the datatuples are (in increasing order) 13, 15,
Bas_tet [7]

Answer:

a) \bar X = \frac{\sum_{i=1}^{27} X_i }{27}= \frac{809}{27}=29.96

Median = 25

b) Mode = 25, 35

Since 25 and 35 are repeated 4 times, so then the distribution would be bimodal.

c) Midrange = \frac{70+13}{3}=41.5

d) Q_1 = \frac{20+21}{2} =20.5

Q_3 =\frac{35+35}{2}=35

e) Min = 13 , Q1 = 20.5, Median=25, Q3= 35, Max = 70

f) Figura attached.

g) When we use a quantile plot is because we want to show the percentage or the fraction of values below or equal to an specified value for the distribution of the data.

By the other hand the quantile-quantile plot shows the quantiles of the distribution values against other selected distribution (specified, for example the normal distribution). If the points are on a straight line we assume that the data values fit very well to the hypothetical distribution selected.

Step-by-step explanation:

For this case w ehave the following dataset given:

13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25, 25, 25, 30,33, 33, 35, 35, 35, 35, 36, 40, 45, 46, 52, 70.

Part a

The mean is calculated with the following formula:

\bar X = \frac{\sum_{i=1}^{27} X_i }{27}= \frac{809}{27}=29.96

The median on this case since we have 27 observations and that represent an even number would be the 14 position in the dataset ordered and we got:

Median = 25

Part b

The mode is the most repeated value on the dataset on this case would be:

Mode = 25, 35

Since 25 and 35 are repeated 4 times, so then the distribution would be bimodal.

Part c

The midrange is defined as:

Midrange = \frac{Max+Min}{2}

And if we replace we got:

Midrange = \frac{70+13}{3}=41.5

Part d

For the first quartile we need to work with the first 14 observations

13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25, 25, 25

And the Q1 would be the average between the position 7 and 8 from these values, and we got:

Q_1 = \frac{20+21}{2} =20.5

And for the third quartile Q3 we need to use the last 14 observations:

25, 30,33, 33, 35, 35, 35, 35, 36, 40, 45, 46, 52, 70

And the Q3 would be the average between the position 7 and 8 from these values, and we got:

Q_3 =\frac{35+35}{2}=35

Part e

The five number summary for this case are:

Min = 13 , Q1 = 20.5, Median=25, Q3= 35, Max = 70

Part f

For this case we can use the following R code:

> x<-c(13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25, 25, 25, 30,33, 33, 35, 35, 35, 35, 36, 40, 45, 46, 52, 70)

> boxplot(x,main="boxplot for the Data")

And the result is on the figure attached. We see that the dsitribution seems to be assymetric. Right skewed with the Median<Mean

Part g

When we use a quantile plot is because we want to show the percentage or the fraction of values below or equal to an specified value for the distribution of the data.

By the other hand the quantile-quantile plot shows the quantiles of the distribution values against other selected distribution (specified, for example the normal distribution). If the points are on a straight line we assume that the data values fit very well to the hypothetical distribution selected.

6 0
3 years ago
8=8p+13−3p please help ​
Elenna [48]

Answer:

-1=p

Step-by-step explanation:

8=8p+13-3p

8-13=8p-3p

-5=5p

-5÷5=5p÷5

-1=p

8 0
3 years ago
A garden supply store sells two types of lawn mowers. The smaller mower costs $249.99 and the larger mower costs $329.99. If the
Butoxors [25]
Therefore, ' 19 ' smaller lawn mover and '11' larger lawn mover were sold.
Step-by-step explanation:
Given:
let the smaller lawn mover be 'x'
let the larger lawn mower be 'y'
According to condition total mover will be
................( 1 )
and total cost will be given as
................( 2 )
To Find:
x =? and y =?
Solution:
Substituting equation 1 in equation 2 we get

Substituting ' y 'in ( 1 ) we get
3 0
2 years ago
What is the domain of f(x)=9-x2
son4ous [18]

The domain is all real number

There is no limit to what x can be

Choice G

5 0
3 years ago
Select all the correct answers.
irina1246 [14]

Operations that can be applied to a matrix in the process of Gauss Jordan elimination are :

replacing the row with twice that row

replacing a row with the sum of that row and another row

swapping rows

Step-by-step explanation:

Gauss-Jordan Elimination is a matrix based way used to solve linear equations or to find inverse of a matrix.

The elimentary row(or column) operations that can be used are:

1. Swap any two rows(or colums)

2. Add or subtract scalar multiple of one row(column) to another row(column)

as is done in replacing a row with sum of that row and another row.

3. Multiply any row (or column) entirely by a non zero scalar as is done in replacing the row with twice the row, here scalar used = 2

6 0
3 years ago
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