$\left\{\begin{array}{ccc}5x+y=-10&|\text{subtract 5x from both sides}\\4x-7y=-8\end{array}\right\\\left\{\begin{array}{ccc}y=-5x-10&|\text{substitute to the second equation}\\4x-7y=-8\end{array}\right\\\\4x-7(-5x-10)=-8\qquad\text{use distributive property}\\\\4x+(-7)(-5x)+(-7)(-10)=-8\\\\4x+35x+70=-8\qquad\text{subtract 70 from both sides}\\\\39x=-78\qquad\text{divide both sides by 39}\\\\\boxed{x=-2}\\\\\text{Put the value of x to the first equation}\\\\y=-5(-2)-10\\\\y=10-10\\\\\boxed{y=0}$

$Answer:\ \boxed{x=-2\ and\ y=0}$

3 0

3 years ago

Read 2 more answers

This is due next period. I need answers and a small explanation/work.

vlada-n [284]

1) Cancel out the common factor which in this case is 8 $\frac{16m^2}{24m^7} = \frac{2m^2}{3m^7}$

2)First apply exponent rule $\frac{n(n+7)}{4n(n+7)}\\$ now cancel out the common factors which are n and n+7 leaving you with $\frac{1}{4}=0.25$

3)Factorize $\frac{(x+2)(x-12)}{x+2}$ cancel out the common factor in this case x+2 leaving you with $x-12$

4) Factorize $\frac{(-3w+1)(3w-1)}{4(3w-1)}$ cancel out the common factor in this case 3w-1 leaving you with $\frac{-3w+1}{4}$

5) In the picture

6)In the picture

I am REALLY tired sorry I wont be able to do the rest, I hope these are helpful :)

6 0

2 years ago