Two solutions were found :<span> x = 1 x = -2
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Answer:
Below.
Step-by-step explanation:
1. Prasha's result is better as she tossed the coin the most times.
Answer: D) csc (2π/3)
<u>Step-by-step explanation:</u>
2π/3 is in Quadrant II
Quadrant II has a negative x-value and a positive y-value.
x-values are: cos & sec
y-values are: sin & csc
tan = y/x so will be negative in Quadrant II
A) sec = -
B) tan = -
C) cos = -
D) csc = + this works!
first solve for the perimeter of the rectangle
2w + 2l = 42
since the length of the rectangle is twice as long as the length and width of the square
2w = l
solve using substitution
2w + 2(2w) = 42
2w + 4w = 42
6w = 42
w = 7
are is length x width. a square has the same length and width
7 x 7 = 49
the area of one square is 49