All categories

4 years ago

Trigonometry help me pls!!

Mathematics

1 answer:

drek231 [11]4 years ago

6 0

let the unknown angle be a

so a+90 + 20= 180

If we take 70°,then area (A)=

$\frac{1}{2} sin70xy$

If we take 90° then area(A)=

[tex] \frac{1}{2} sin90x \times 10 = \frn

therefore y=10.64 cm

By using pythagoras theorem

y^2=x^2+10^2

or, x^2=y^2-100

or, x^2=10.64^2-100

or,x^2=13.2096

or, x= 3.63 cm

You might be interested in

What is the distance between points A and B?

diamong [38]

Answer:

Therefore, the distance between points A and B is approximately equal to 6.4 inches.

6 0

3 years ago

Read 2 more answers

AZ recycled pays the rates of the chart below for recycling certain material if 0% for number of pounds of copper make recycled

Paraphin [41]

What is the question???

8 0

3 years ago

Whats the correct answer?

strojnjashka [21]

Answer:

its the 4 one

Step-by-step explanation:

5 0

3 years ago

Simplify the given expression.

forsale [732]

Since you can only perform addition and subtraction on variables that have the same variable following them, the correct answer is B. 3 - 2i.
Here's why:
1 + 2 + (3i - 5i) =
3 - 2i

3 0

3 years ago

Read 2 more answers

Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De

Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable X represent the time a child spends waiting at for the bus as a school bus stop.

The random variable X is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is, $\lambda=\frac{1}{\mu}=\frac{1}{7}$ .

The probability density function of X is:

$f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0$

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

$P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx$

$=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148$

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

6 0

3 years ago