Answer:
YES
Step-by-step explanation:
Find the equation of the line written as, y = kx. The graph shows a proportional relationship between y and x.
Constant of proportionality/unit rate/slope (k) = rise/run = ⁵/4.
Substitute ⁵/4 in y = kx
We would have:
y = ⁵/4x.
Using the equation of the line, we can know if a given point is on the line by plugging the value of x and y coordinates of the point into the equation. If it makes the equation true, then it is a point on the line. If it doesn't make the equation true, then it isn't a point on the line.
Let's plug in (16, 20) into y = ⁵/4x.
Thus substitute x = 16 and y = 20, we have:
[tex] 20 = \frac{5}{4}(16) [/trex]
[tex] 20 = (5)(4) [/trex]
[tex] 20 = 20 [/trex]
It makes the equation true. Therefore, the point, (16, 20) is a point on line l.
Answer:
Assuming that it's a rectangular track and the units are 15x25 yards, the perimeter is 80 yards.
Explanation:
Remember to find the perimeter of a non-circular shape you just add up all of the side lengths together. In this case, I believe it's a 15x25 yard rectangle, so you ad 15 + 15 + 25 + 25 to get a total of 80 yards.
If you look at the image you can see that it says “x - 2 is greater than/equal to 0
Answer:
poloygons with right angles
Step-by-step explanation:
