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3 years ago

Find the difference: 20 - 80 -12-15

Mathematics

2 answers:

zavuch27 [327]3 years ago

8 0

Answer: -87

Step-by-step explanation:

Fudgin [204]3 years ago

6 0

Answer:

-60 and then -27 is the answer

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Explain how you can use strategy guess check and revise to solve problems that involve a given area when the relationship betwee

Aleksandr-060686 [28]

You can try finding numbers that are close to what you think you can use for exaple lets say we want to find the answer to 54x34 you could multiply 50x30 to get an estimated answer

3 0

3 years ago

Find the limit

Lana71 [14]

Step-by-step explanation:

<h3>Appropriate Question :-</h3>

Find the limit

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

$\large\underline{\sf{Solution-}}$

Given expression is

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

On substituting directly x = 1, we get,

$\rm \: = \: \sf \dfrac{1-2}{1 - 1}-\dfrac{1}{1 - 3 + 2}$

$\rm \: = \sf \: \: - \infty \: - \: \infty$

which is indeterminant form.

Consider again,

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

can be rewritten as

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 3x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 2x - x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( x(x - 2) - 1(x - 2))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ {(x - 2)}^{2} - 1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 2 - 1)(x - 2 + 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)(x - 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)}{x(x - 2)}\right]$

$\rm \: = \: \sf \: \dfrac{1 - 3}{1 \times (1 - 2)}$

$\rm \: = \: \sf \: \dfrac{ - 2}{ - 1}$

$\rm \: = \: \sf \boxed{2}$

Hence,

$\rm\implies \:\boxed{ \rm{ \:\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right] = 2 \: }}$

$\rule{190pt}{2pt}$

7 0

2 years ago

Read 2 more answers

−2 1/6 divided by 1 1/4<br> 100 points

galina1969 [7]

Answer:

-1 11/15

Step-by-step explanation:

<u>−2 1/6 divided by 1 1/4:</u>

-2 1/6 ÷ 1 1/4 =
- 13/6 ÷ 5/4 =
- 13/6 × 4/5 =
- 26/15 =
-1 11/15

8 0

3 years ago

Read 2 more answers

Use the Law of Sines to solve the triangle.<br> 6.) A=60 degrees, a=9, c=10

lesantik [10]

SinA /a = sin C / c
sin 60/9 = sin C / 10
(√3/2)/9 = sinC/ 10
√3/18 = sin C / 10
so c will be sin inverse ((10√3)/10)

8 0

3 years ago

. Water in a 10 gallon tank is draining at a rate of 2 gallons per hour. Water in a separate tank is filling at a rate of 4 gall

taurus [48]

Answer:

Step-by-step explanation:

Water in a 10 gallon tank is draining at a rate of 2 gallons per hour.

= 10 - 2x

Water in a separate tank is filling at a rate of 4 gallons per hour.

= 10 + 4x

Equating both Equations together

10 - 2x = 10 + 4x

10 - 10 = 4x - 2x

How long until the tanks have the same amount of water?

Let the time = x

7 0

3 years ago