Hello,
An example of a decimal between 0.5 and 0.75 is 0.6, written as 3/5 as a fraction in its simplest form.
Hope this helps!
Answer: 10:55
Step-by-step explanation:
Taking statement at face value and the simplest scenario that commencing from 08:00am the buses take a route from depot that returns bus A to depot at 25min intervals while Bus B returns at 35min intervals.
The time the buses will be back at the depot simultaneously will be when:
N(a) * 25mins = N(b) * 35mins
Therefore, when N(b) * 35 is divisible by 25 where N(a) and N(b) are integers.
Multiples of 25 (Bus A) = 25, 50, 75, 100, 125, 150, 175, 200 etc
Multiples of 35 (Bus B) = 35, 70, 105, 140, 175, 210, 245 etc
This shows that after 7 circuits by BUS A and 5 circuits by Bus B, there will be an equal number which is 175 minutes.
So both buses are next at Depot together after 175minutes (2hr 55min) on the clock that is
at 08:00 + 2:55 = 10:55
I would have to say That i see 8
Answer:
miss girl-
Step-by-step explanation:
The answer is 5,600.00
Answer:
(14,-1)
Step-by-step explanation:
okay so first you need to use the "x=4y+10" in the first equation.
Rewrite as
3(4y+10) +11y=7
Distribute the 3(4y+10)
Rewrite as
12y+30
You'll have the equation
12y +30 +11y= 7
Subtract the 7 from both sides
12y+30+11y-7= 0
Combine like terms
23y+23=0
the best thing to do here is divide the equation by 23.
23/23 = 1
you'll have
y + 1 = 0
this simplifies to
y= -1
use this y value to solve for x
the easiest way to do this is start with the equation
x = 4y +10
Substitute the y for -1
x = -4(-1) +10
x = 4 +10
x = 14
the solution point is
(14,-1)
