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alexira [117]
3 years ago
8

A polynomial equation with rational coefficients has the roots 7 + *sqrt* 3 , 2 - *sqrt* 6. Find two additional roots.

Mathematics
2 answers:
topjm [15]3 years ago
7 0
If the coefficients of a polynomial equation are rational, then the irrational roots have to come in conjugate pairs.
The conjugate of 7 +√ 3 is 7 - √ 3 and the conjugate of 2 - √ 6 is 2 + √ 6.
Answer:
A ) 7 - √ 3 ,  2 + √ 6
Ganezh [65]3 years ago
5 0

Answer:

option: A

Step-by-step explanation:

" if for a polynomial with rational coefficients has irrational roots then these irrational roots will always appear in pair " .

we are given that 7+\sqrt{3} and 2-\sqrt{6} are two roots of a polynomial equation with rational coefficients, then it's complex conjugate is also a root of this polynomial equation i.e. ' 7-\sqrt{3} ' and '  2+\sqrt{6} ' are also roots of this polynomial equation.

Hence, option A is correct.


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- (64 - 36 + 5) + (45 - 87) = ?
adoni [48]

Answer:

its -75

Step-by-step explanation:

8 0
3 years ago
Use the empirical rule to solve the problem. The annual precipitation for one city is normally distributed with a mean of 288 in
nadezda [96]

Answer:

z=-1.99

z=1.99

And if we solve for a we got

a=288 -1.99*3.7=214.4

a=288 +1.99*3.7=295.4

And the limits for this case are: (214.4; 295.4)

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the annual precipitation of a population, and for this case we know the distribution for X is given by:

X \sim N(288,3.7)  

Where \mu=288 and \sigma=3.7

The confidence level is 95.44 and the signficance is 1-0.9544=0.0456 and the value of \alpha/2 =0.0228. And the critical value for this case is z = \pm 1.99

Using this condition we can find the limits

z=-1.99

z=1.99

And if we solve for a we got

a=288 -1.99*3.7=214.4

a=288 +1.99*3.7=295.4

And the limits for this case are: (214.4; 295.4)

8 0
3 years ago
Paul’s account balance is less than -$50. What is a possible balance for paul’s account? Explain.
RoseWind [281]

Answer:

Step-by-step explanation:

-50 plus so above the number so like -51.5

7 0
3 years ago
Find the product and write the answer as a trinomial in standard form (x+2y) (3x-5y)
kodGreya [7K]

Answer:

3x^2 + xy - 10y^2

Step-by-step explanation:

1. Use the FOIL method

3x ^​2  − 5xy + 6yx − 10y ^2

​​2. Collect like terms

3x ^2 ​ + (−5xy + 6xy) − 10y^​2

​​3.  Simplify

3x ^2 ​ + xy − 10y^​2

​​  

8 0
3 years ago
A box with a square base and no top is to be built with a volume of 4000 in3. find the dimensions of the box that requires the l
vekshin1

Let the length of the square base be x inches .

And the height of the box be y inch .

Volume = x*x*y

4000 = x *x *y

y = \frac{4000}{x^2}

S = x*x + 2xy + 2 x y

S = x^2 + 4 xy

S = x^2+ 4x* \frac{4000}{x^2}

S = x^2 + \frac{16000}{x}

S ' = 2x - \frac{16000}{x^2}

S ' =0

2x - \frac{16000}{x^2}=0

2x^3 - 16000 = 0

x^3 = 8000

x = 20

y =  \frac{4000}{20^2} = \frac{4000}{400} = 10

6 0
3 years ago
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